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For this problem, the Atomic Mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.
.06 grams C / (12.0 grams) × (6.02 × 1023 atoms) = 3.01 × 1021 atoms
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoThe gram atomic mass of carbon is 12.01, so that 6.5 grams contains 6.5/12.01 moles = 0.54 mole, to the justified number of significant digits. Multiplying this by Avogadro's number, 6.02 X 1023, gives 3.3 X 1023 atoms, to the justified number of significant digits.
Wiki User
∙ 11y ago12/6 = 2
so: (6.023*10^23)/2 = 301150000000000000000000 atoms of C12.
Wiki User
∙ 10y ago6 grams 12C (1 mole 12C/12.01 grams)
= 0.5 moles 12C
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Wiki User
∙ 12y agoThe answer is 36,132 847 74.1023 carbon atoms.
Wiki User
∙ 11y ago12.0107 grams per mole of carbon / 6.05 grams = 1.98524 moles
Wiki User
∙ 14y agoAtoms in 6 grams of 12C: 3,011070895.1023
Wiki User
∙ 15y ago0.029 lead
Wiki User
∙ 11y ago0.5
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