The same.
0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
0.424 moles of 0xygen
Also 0,1 mole carbon dioxide.
0.217 Mole
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms.
if you mean 10^22 O atoms, then this is how you do it: (8.16X10^22)/2=4.08X10^22 so there are 4.08X10^22 molecules, divided by 6.022X10^23(1 mole) is .06775, so there are that many moles of CO2. If you wanted to know how many moles of overall atoms there were, there's 4.08X10^22 molecules, 1 C in each so 4.08X10^22 C, and 8.16X10^22 O=1.224X10^23, and that's how many atoms, so that divided by 1 mole is (most accurate answer i can get you) .2032547326 moles of atoms so .2032547326 moles of atoms or .06775 moles of molecules/CO2
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 167 mole of CO2 has 167 mole of carbon atoms.
C + O2 ==> CO2At STP 1 mole CO2 = 22.4 L 10L x 1 mole/22.4 L = 0.446 moles CO2 needed 1 mole C = 1 mole CO2 Therefore you need 0.446 moles C grams C = 0.446 moles C x 12 g/mole = 5.36 grams = 5 g (to 1 significant figure)
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
This is a chemical calculation. 2.5 moles will C reacting with O2.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms.
if you mean 10^22 O atoms, then this is how you do it: (8.16X10^22)/2=4.08X10^22 so there are 4.08X10^22 molecules, divided by 6.022X10^23(1 mole) is .06775, so there are that many moles of CO2. If you wanted to know how many moles of overall atoms there were, there's 4.08X10^22 molecules, 1 C in each so 4.08X10^22 C, and 8.16X10^22 O=1.224X10^23, and that's how many atoms, so that divided by 1 mole is (most accurate answer i can get you) .2032547326 moles of atoms so .2032547326 moles of atoms or .06775 moles of molecules/CO2
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 167 mole of CO2 has 167 mole of carbon atoms.
C + O2 ==> CO2At STP 1 mole CO2 = 22.4 L 10L x 1 mole/22.4 L = 0.446 moles CO2 needed 1 mole C = 1 mole CO2 Therefore you need 0.446 moles C grams C = 0.446 moles C x 12 g/mole = 5.36 grams = 5 g (to 1 significant figure)
(90 g CO2 / (12.0+2*16.0) g/mol CO2) = 2.05 mol CO2 = 2.05 mol C2.05 mol C * 12.0 g/mol C = 24.5 g C
Divide mass (g) by molar mass (g/mol) : 30 g C2H2 = 30/26 g 35 g H2O = 35/18 g
At STP 2.21 L CO2 is 0.0987 moles of CO2 since 1 mole = 22.4L. One mole CO2 contains 1 mole of C so there are 0.0897 moles of C. Grams of C = 0.0987mole x 12g/mole = 1.18 grams.
Balanced equation. C + O2 -> CO2 22.2 grams carbon (1 mole C/12.01 grams)(1 mole CO2/1 mole C) = 1.85 moles carbon dioxide produced -------------------------------------------------
For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2= 44.0 grams1.50 moles CO2 × (44.0 grams) = 66.0 grams CO2
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams33.0 grams C / (44.0 grams) = .750 moles CO2