3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3)
= 3.5 moles
.06 moles
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
Calcium carbonate is CaCO3 and has 5 atoms. One calcium (Ca), one carbon (C) and three oxygen (O) atoms
Calcium Carbonate (CaCo3) has one calcium (Ca) atom, one carbon (C) atom and three oxygen (O3) atoms.
The constituent elements of calcium carbonate are calcium, carbon, and oxygen.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
2,8 moles of calcium carbonate have 240,208 g.
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Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
.06 moles
Calcium carbonate contains 3 elements, calcium, carbon, and oxygen. The formula is CaCO3.
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
Calcium carbonate is CaCO3 and has 5 atoms. One calcium (Ca), one carbon (C) and three oxygen (O) atoms
Calcium Carbonate (CaCo3) has one calcium (Ca) atom, one carbon (C) atom and three oxygen (O3) atoms.
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
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250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate