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For this you need the Atomic Mass of Cr. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel.

11.9 moles Cr × (52.0 grams) =618.8 grams Cr

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Demond Stroman

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2y ago
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14y ago

For this you need the atomic mass of Cr. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.

11.9 moles Cr × (52.0 grams) =618.8 grams Cr

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14y ago

Assuming the Cr is existing purely as Cr, and is not bonded to another Cr atom or any other compound:

First we have to calculate the number of moles of Cr. This is the mass divided by the molecular weight, so 14.9 / 51.996. This is approx. equal to 0.287.

We then need to multiply this by Avogadro's number, which is the number of atoms in one mole. So we have 0.287 x ( 6.022 × 1023 ), which is equal to 1.73 x 1023 atoms.

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12y ago

Let us use comparative stoichiometry to find out. ( I am betting on the hydrogen out of experience )

1.1 grams hydrogen (1 mole H/1.008 grams)(6.022 X 1023/1 mole H)

= 6.6 X 1023 atoms of hydrogen

=========================================

6.6 X 1023/1.7 X 1023

= 3.8 times more hydrogen atoms than chromium atoms

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Wiki User

10y ago

Atomic mass of chromium, Cr = 52.0
Amount of Cr = 11.9/52.0 = 0.229mol
There are 0.229 moles of chromium in a 11.9g pure chromium sample.

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10y ago

1.10 g of hydrogen atoms has more atoms.

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7y ago

Approx 0.2635 moles.

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Makayla Randall

Lvl 2
1y ago

0.229

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Q: Which has more atoms 1.1 g of hydrogen atoms or 14.7g of chromium atoms?
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