At standard temperature and pressure, 1 mole of any gas occupies 22.4 liters of space. So, 65.8 liters would be 65.8/22.4=2.9375, so approximately 3 moles.

At STP, one mole of any gas occupies 22.4 liters. This is called molar volume. 113.97 liters Ã· (22.4 L/mol) = 5.09 moles Then convert moles to molecules (1 mole = 6.02 Ã— 1023 molecules) 5.09 moles Ã— (6.02 Ã— 1023 molecules/mol) = 3.06 Ã— 1024 molecules

At standard temperature and pressure (STP), 1 mole of any gas occupies about 22.4 liters of space. If you have 3.75L of a gas, then 3.75/22.4=0.17 moles.

A cubic decimeter is a liter, so we're talking 50L of oxygen gas at STP. 1mol of any gas at STP occupies 22.4L of space, so 50/22.4 = about 2.2mol of oxygen.

What you mean to say is, ' what volume in liters is occupied by 35 moles of ' something ' at STP. ' Use PV = nRT (1 atm)(volume) = (35 moles)(0,08206 Latm/molK)(298.15 K) = 856 Liters of what ever you have.

I forget the easier way, so we do it this way. Use PV = nRT and find moles O2. (1 atm)(44.8 liters) = n(0.08206 L*atm/mol *K)(298.15 K) = 1.831 moles O2 1.831 moles O2 (32.0 grams/1 mole O2) = 58.6 grams of O2

Acetylene is C2H2, with a molar mass of 26g/mol. 49.6g of it = 1.9 moles. At STP, 1 mole of any gas occupies a volume of 22.4 liters, so 1.9 moles at STP would have a volume of 42.56 liters.