answersLogoWhite

0


Best Answer

To answer this, we must first know what STP is. STP (Standard Temperature and Pressure) is when the environment is at the following:

  • 0oC
  • 1 Atmosphere of Pressure (101.325 kPa)

To figure out any missing units in a gas equation, we use the Ideal Gas Law, PV=nRT.

  • 'P' is pressure in kPa
  • 'V' is volume in litres or dm3
  • 'n' is the number of mol
  • 'R' is the gas constant = 8.314
  • 'T' is temperature in kelvin

To work out the number of mol, we substitute in the calues we have and solve for n. This gives us 101.325kPa*5.6dm3=n*8.314*273K. Therefore, n=0.25 mol.

Alternatively, we could simply use the fact that 1 mol of any gas at STP takes up 22.4 litres. So 5.6/22.4 leaves us with 0.25 mol.

User Avatar

Wiki User

14y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

9y ago

Methane has the chemical formula of CH4 and a density of .000667 grams per cubic centimeter. This means there are 3.74 grams and 0.233 moles present.

This answer is:
User Avatar

User Avatar

Wiki User

7y ago

5.6 L of ideal gas contain 0,25 moles.

This answer is:
User Avatar

User Avatar

Wiki User

15y ago

n = 5.6 L x (1 mol / 22.4 L) = 0.25 mol

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

223.2 mol :)

This answer is:
User Avatar

User Avatar

Wiki User

6y ago

The number of argon moles is 0,25.

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

22

This answer is:
User Avatar

User Avatar

Wiki User

12y ago

22 mol

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

0.25 mole

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

0.25 moles

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many moles of argon (Ar) are present in 5.6 liters of argon gas a STP?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many moles of argon gas Ar are present in 5.6 liters of argon gas at standard conditions?

0.25 moles, approx.


How many moles are present in 8.4 liters of nitrous oxide at STP?

8,4 liters of nitrous oxide at STP contain 2,65 moles.


How many moles of KCL are present in 50.0ml of a 0.552 M solution?

Molarity = moles of solute/Liters of solution ( 50.0 ml = 0.05 Liters ) 0.552 M KCl = moles/.0.05 liters = 0.0276 moles of KCl


How many moles of HCl are present in 40ml of a 0.035M solution?

Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============


How many moles of kbr are present in 25ml of a 1.5 M solution?

Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters ) 1.5 M KBr = moles KBr/0.025 Liters = 0.038 moles potassium bromide ------------------


How many moles of sodium chhloride are present in 22.0 ml of 0.500 m solution?

Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------


How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?

Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------


How many moles of argon are in 37.9 g of argon?

moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles


How many moles of sodium ions are present in 2.50 L of 0.300 M Na3PO4?

Molarity = moles of solute/Liters of solution 0.300 M Na3PO4 = moles Na3PO4/2.50 Liters = 0.75 moles Na3PO4


How many moles of argon are found in a 5L sample of argon at STP?

Approx 0.223 moles.


How many moles of helium gas (he) are present in 7.2 liters of helium gas at standard conditions?

The number of moles of helium is 0,32.


How many moles of solute are present in 1.5 liters of 1.33 M of Na2SO4?

The answer is approx. 2 moles (for anhydrous sodium sulfate).