one mole of any element is equals to its gam(Gram Atomic Mass)
and one mole of any molecule is also equals to that molecules gram Atomic Mass.
Lets calculate the gram molecular mass of water :
h2o = 2 hydrogen atoms, 1 oxygen atom
= 2 hydrogen x 1g (gram atomic mass of hydrogen) + 1 oxygen x 16g (gram atomic mass of oxygen)
= 2 + 16
= 18g
Therefore 1 mole of water contains 18grams.
To determine this, we must first find the molar mass of H2O which is 18.01528 g/mol. (Take the atomic mass of H X2 since 2 H atoms present, + atomic mass of O).
Then we must divide mass by molar mass.
So, n= 1.00g/18.01528g/mol
n= 0.055508 mol
earlier responses gave answer to fewer decimal points, users should give number of significant figures relevant to their application
The molar mass of a water molecule is 18.02 grams per mole. If given the mass of water, you can use this molar mass as a conversion factor:
1g H2O x (1mol H2O / 18.02g H2O) = 0.0555mol H2O
Simple answer? 18g
A mole is the formula mass in grams.
Mass of H = approx 1
Mass of O = approx 16
Easy
One mole of water has a mass of 18 grams.
The answer is 0,0555 moles.
137g
yes, one mole of cadmium is 112 grams, one mole of gold is only 2 grams.
17.32 moles H2O (2 moles H/1 mole H2O) = 34.64 moles hydrogen
Because 2Li + O2 --> Li2O2 moles Li produces 1 mole Li2O3.04Li + --> 1.52 O2 --> 1.52 Li2O1.52 moles Li2O arw formed.
There are four molecules of water in 4H2O. One molecule of water is written as H2O. The subscript 2 tells you that there are two H(hydrogen) atoms. Since there is no subscript after the O there is one O(oxygen) atom. Now back to 4H2O. The coefficient 4 tells you there are four molecules of H2O. Therefore there are eight H(hydrogen) atoms and four O(oxygen) atoms.
1 mole H2O = 18.02g --- water is H2O ... 2 x 1.008 + 1 x 15.996 = 18.012 g/mole = 18.01 grams
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams500.0 grams H2O / (18.0 grams) = 27.8 moles H2O
To teach you how to do this problem: 1. Look at the Periodic Table. O =16 grams/mole, H =1.01 grams/mole 2. Calculate the Molecular Weight of Water. 1*O + 2*H: 16+2.02=18.02g/mole 3. Divide the mass of what you have by the Molecular Weight: 35.1g H2O/(18.02 g H2O/mole H2O) 4. The units g H2O cancel leaving you with mole H2O. 5. 35.1 grams H2O= 1.95 moles H2O
CO2 + H2 <-> CO + H2O all one to one ( I assume that 99.1 is grams. Always units!!!! ) 99.1 grams H2O (1 mole H2O/18.016 grams)(1 mole H2/1 mole H2O) = 5.50 moles of hydrogen gas needed If that was 99.1 moles water vapor then it would take 99.1 moles hydrogen gas at a one to one ratio.
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams.417 grams H2O / (18.0 grams) = .0232 moles H2O
You must mean; how many grams of O ( one atom oxygen ) 1.23 X 10^24 molecules H2O (1 mole H2O/6.022 X 10^23)(1 mole O/1 mole H2O)(16 grams/1 mole O) = 32.7 grams of oxygen
The answer is 165,23 grams.
72 grams
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O=18.0 grams235 grams H2O / (18.0 grams) = 13.1 moles H2O
For this you need the atomic (molecular) mass of H2O. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. H2O= 18.0 grams2.5 moles H2O × (18.0 grams) = 45.0 grams H2O
36 grams