answersLogoWhite
notificationBell

Top Answer
User Avatar
Wiki User
Answered 2010-06-21 16:37:43

2 atoms (molecules) of hydrogen are needed to react with oxygen to form water.

001
๐Ÿ™
0
๐Ÿคจ
0
๐Ÿ˜ฎ
0
๐Ÿ˜‚
0
User Avatar

Your Answer

Related Questions


Answer: 7 moles hydrogen and 3,5 moles oxygen.



How many moles of magnesium are needed to react with 16 g of molecular oxygen?





The chemical equation for hydrogen gas and oxygen gas combining to form water is as follows: 2H2 (g) + O2 (g) ---> 2H2O (l). This means that for every 1 mole of oxygen gas reacting, two moles of hydrogen gas are needed. So if 0.50 moles of oxygen gas react to form one mole of water, then one mole of hydrogen gas was used.


The minimum number of moles of 02 that are needed to completely react with 16 moles of NH3 is 12 moles oxygen.


4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.


Five moles of O2 are needed to react with 2.00 moles C2H2. The symbol O2 stands for Oxygen, and C2H2 stands for acetylene.





The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.




10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.


I assume you mean this reaction. N2 + 3H2 --> 2NH3 0.90 moles N2 (3 moles H2/1 mole N2) = 2.7 moles hydrogen gas needed =====================



Four (4) moles of magnesium oxide are formed when 4 moles of magnesium react with oxygen.



To form NH3, I assume. Balanced equation. N2 + 3H2 -> 2NH3 0.85 moles N2 (3 moles H2/1 mole N2) = 2.6 moles hydrogen gas needed ---------------------------------------------


This is the Sabatier reaction or Sabatier process (the reaction of hydrogen with carbon dioxide at elevated temperatures and pressures in the presence of a nickel catalyst to produce methane and water) CO2 + 4H2 → CH4 + 2H2O The hydrogen is required both to react with the carbon and the oxygen and all of this must be accounted for to produce the 76.6 moles of water. From the equation 4 moles of hydrogen reacts with 1 mole of carbon dioxide ot produce 2 moles of water. The production of 76.6 moles of water requires 153.2 moles of hydrogen.


No. Hydrogen and oxygen react with each other to form water.