2 atoms (molecules) of hydrogen are needed to react with oxygen to form water.
Answer: 7 moles hydrogen and 3,5 moles oxygen.
The nunber of moles of oxygen is 2,5.
How many moles of magnesium are needed to react with 16 g of molecular oxygen?
We need theoretically 22,23 moles hydrogen.
84,2 moles hydrogen are needed.
3 moles of magnesium are needed.
The chemical equation for hydrogen gas and oxygen gas combining to form water is as follows: 2H2 (g) + O2 (g) ---> 2H2O (l). This means that for every 1 mole of oxygen gas reacting, two moles of hydrogen gas are needed. So if 0.50 moles of oxygen gas react to form one mole of water, then one mole of hydrogen gas was used.
The minimum number of moles of 02 that are needed to completely react with 16 moles of NH3 is 12 moles oxygen.
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
Five moles of O2 are needed to react with 2.00 moles C2H2. The symbol O2 stands for Oxygen, and C2H2 stands for acetylene.
The value is 3,45 moles oxygen.
We need 4,8 moles acetylene.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
4 Mg + 2 O2 --> 4 MgOThe answer is two
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
I assume you mean this reaction. N2 + 3H2 --> 2NH3 0.90 moles N2 (3 moles H2/1 mole N2) = 2.7 moles hydrogen gas needed =====================
192 g oxygen are needed.
Four (4) moles of magnesium oxide are formed when 4 moles of magnesium react with oxygen.
Two moles of nitrogen are needed.
To form NH3, I assume. Balanced equation. N2 + 3H2 -> 2NH3 0.85 moles N2 (3 moles H2/1 mole N2) = 2.6 moles hydrogen gas needed ---------------------------------------------
This is the Sabatier reaction or Sabatier process (the reaction of hydrogen with carbon dioxide at elevated temperatures and pressures in the presence of a nickel catalyst to produce methane and water) CO2 + 4H2 → CH4 + 2H2O The hydrogen is required both to react with the carbon and the oxygen and all of this must be accounted for to produce the 76.6 moles of water. From the equation 4 moles of hydrogen reacts with 1 mole of carbon dioxide ot produce 2 moles of water. The production of 76.6 moles of water requires 153.2 moles of hydrogen.
No. Hydrogen and oxygen react with each other to form water.
We need 1,08 moles oxygen.
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