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0.1 mols of N2 * 3 mols of H3/1 mol of N2

In other words, for 0.1 mols of N2 times 3 mols of H3 for ever mol of N2.

I order to find the other numbers you are going to need a balanced equation:

N2+3H2→ 2NH3

So you would have 0.3 mols.

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12y ago
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11y ago

Well this a difficult question. It depends what you are making, there are over 20 binary compoundsno nitrogen and hydrogen. The best known of which is ammonia, NH3 but others include hydrazine, N2H4 triazine N3H5.

As an example in the reaction of N2 with H2 to form ammonia.

N2 + 3H2 -> 2NH3

If you take two moles of nitrogen then you will need 6 moles of hydrogen.

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12y ago

To form NH3, I assume.

Balanced equation.

N2 + 3H2 -> 2NH3

0.85 moles N2 (3 moles H2/1 mole N2)

= 2.6 moles hydrogen gas needed

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13y ago

If ammonia is being made

1.5 moles H2.

N2 + 3(H2) = 2NH3

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8y ago

Two moles of nitrogen are needed.

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12y ago

2 moles

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14y ago

2 moles

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11y ago

1

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Q: How many moles of H2 are needed to react with 0.85 moles of N2?
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