Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
0.051 molesWe know the molecular weight of NaCl is 58.443 g/mol and that the formula for the dissociation of salt in water looks like this:NaCl (aq)-->Na+ + Cl-So we can see that there is a one to one mole ratio between NaCl and sodium ions. All we have to do to find the moles of ions is3.00g * 1mol NaCl/58.443 g NaCl = 0.051 mol NaClFrom here we apply the ratio of 1 mol NaCl : 1 mol Na+ (though, since the ratio is one, it's not really necessary in this case):0.051 mol NaCl * 1 mol Na+/1mol NaCl = 0.051 mol Na+
As the molar mass of NaCl is 58.5 g/mol, 1.6 moles weight is 93.6 grams.
1.5 moles
Divide by molar mass of NaCl (not NaCI ! ) which is 58.44 g/mol NaCl.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
mol = mass/Mr mol = 737/ 58.44 moles of NaCl = 12.61
13(g) / 58.5(g/mol) = 0.22 mol NaCl
0.051 molesWe know the molecular weight of NaCl is 58.443 g/mol and that the formula for the dissociation of salt in water looks like this:NaCl (aq)-->Na+ + Cl-So we can see that there is a one to one mole ratio between NaCl and sodium ions. All we have to do to find the moles of ions is3.00g * 1mol NaCl/58.443 g NaCl = 0.051 mol NaClFrom here we apply the ratio of 1 mol NaCl : 1 mol Na+ (though, since the ratio is one, it's not really necessary in this case):0.051 mol NaCl * 1 mol Na+/1mol NaCl = 0.051 mol Na+
1 mol of NaCl is 58,44 g.
1 mole of NaCl is 58.44 g 200 g NaCl * (1 mol NaCl/58.44 g NaCl) = 3.422 mol NaCl There are about 3.4 moles in 200 grams of NaCl.
As the molar mass of NaCl is 58.5 g/mol, 1.6 moles weight is 93.6 grams.
1.5 moles
There are two moles of sodium ions in two moles of sodium chloride.
Every mol of NaCl contains a mol of Na, weighting 23 grams, and a mol of Cl, weighing 35.5 grams. So, every mol of NaCl weights 58,5 (=23+35.5) grams. Therefore, 145 moles of NaCl weights 8482.5 grams.
0.0002 mol NaCl/mLmolarity = (moles solute)/(L of solution)0.20 M NaCl = 0.20 mol NaCl/L1 L = 1000 mL0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)
Divide by molar mass of NaCl (not NaCI ! ) which is 58.44 g/mol NaCl.