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Josianne Prohaska

Lvl 13
1y ago
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Wiki User

13y ago

1mol of Fe -------------------> 55.8g

x ------------------>111.8g

55.8x = 111.8 * 1

x = 111.8 * 1/55.8

x = 2.00moles

therefor there are 2.00 moles of iron in 111.8g of iron

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Wiki User

14y ago

4.03 X 10^24 atoms Fe/6.022 X 10^23

= 6.69 moles o9f Fe

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Wiki User

11y ago

divide by Avogadro's number

3.25E24 / 6.022E23 = 5.40 moles

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Wiki User

12y ago

5.23 moles

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Wiki User

12y ago

5.23 moldes

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Wiki User

10y ago

5.23 moles

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Wiki User

11y ago

88

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Q: How many moles of iron are present in 3.15E24 atoms of iron?
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