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How many moles of oxygen are produced when 7.5 moles of potassium chlorate decompose completely?
Wiki User
∙ 7y ago
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
Wiki User
∙ 12y ago
Wiki User
∙ 8y agoThe reaction is:
KOH + HCl = KCl + H2O
The answer is 5 moles KCl.
Wiki User
∙ 7y agoThe reaction is:
2 KClO3 = 2 KCl + 3 O2
38,4 moles of oxygen are produced.
Wiki User
∙ 7y agoPotassium chlorate = KClO3
Decompostion: 2KClO3 ==> 3O2 + 2KCl
7.5 moles KClO3 x 3 mole O2/2 moles KClO3 = 11.25 moles O2
Wiki User
∙ 6y agoBalanced equation: 2KClO3 --> 2KCl + 3O2
6 mol KClO3 = 3 x 2 mol KCl, so the number of moles O2 that can be produced by 6 mol KClO3 is:
3 x 3 mol O2 = 9 mol O2.
Wiki User
∙ 7y ago0,0835 moles
Wiki User
∙ 7y ago11,25 moles of oxygen are produced.
Wiki User
∙ 6y ago8,55 moles of oxygen are produced.
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How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?
Nothing is produced, 500g potassium chlorate will be the same 500 g potassium chlorate after reaction. Actually there is no reaction at all.
What gas is produced when you mix hydrogen peroxide with potassium iodide?
Oxygen gas is produced. The hydrogen peroxide will decompose to give water and oxygen, potassium Iodide is acting as a catalyst 2H2O2(l) ------> 2H2O(l) + O2(g)
How many moles of oxygen are produced from twelve moles of potassium chlorate?
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
What is the red bit on a match?
On a safety match (the kind you strike on a box) the red bit is primarily a compound called potassium chlorate. The strip on the box is red phosphorous. When you strike it on the box the two compounds create an explosive mixture which is then ignited by the heat and sparks produced by friction between the strip and the match head. Strike anywhere matches put the two compounds together on the match, the red is the phosphorous and the white tip is potassium chlorate. When you strike the match they mix and catch fire similar to striking a safety match on the box.
How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?
Nothing is produced, 500g potassium chlorate will be the same 500 g potassium chlorate after reaction. Actually there is no reaction at all.
If 25.0 grams of potassium chlorate decomposes, how many grams of potassium chloride will be produced What is the limiting reactant?
I Don't knows Sorry
How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
What gas is produced when you mix hydrogen peroxide with potassium iodide?
Oxygen gas is produced. The hydrogen peroxide will decompose to give water and oxygen, potassium Iodide is acting as a catalyst 2H2O2(l) ------> 2H2O(l) + O2(g)
How many moles of oxygen are produced from twelve moles of potassium chlorate?
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
Is CO2 produced when products decompose?
yes
When 36.3 g of potassium chlorate is heated 22.1 g of potassium chloride is produced What mass of oxygen is produced?
Equation: 2KClO3 + Cl2 ---> 2KCl + 3O2 + Cl2 1. Solve for the number of moles of KClO3 in 36.3 g. (.2962 molKClO3) 2. Multiply that value by (3/2), from the equation's coefficients. (.4447 molO2) Note: A BCA table could also be used. 3. Solve for the mass of .4447 molO2. 14.2 grams of oxygen would be produced.
A How many moles of O2 were produced b What percent of the mixture was KClO3 and KCl?
A 1.80-gram mixture of potassium chlorate, kclo3, and potassium chloride, kcl, was heated until all of the kclo3 had decomposed the liberated oxygen, after drying, occupied 405 ml at 25C when the barometric pressure was 745 torr. This is the problem and the questions were... a. How many moles of O2 were produced? b. What percent of the mixture was KClO3? KCl? Please help!!
How many moles of oxygen are produced from 14 moles of potassium chlorate?
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
What is the red bit on a match?
On a safety match (the kind you strike on a box) the red bit is primarily a compound called potassium chlorate. The strip on the box is red phosphorous. When you strike it on the box the two compounds create an explosive mixture which is then ignited by the heat and sparks produced by friction between the strip and the match head. Strike anywhere matches put the two compounds together on the match, the red is the phosphorous and the white tip is potassium chlorate. When you strike the match they mix and catch fire similar to striking a safety match on the box.
Hoy many moles of potassium nitrate are produced when 2 moles of potassium phosphate react wth 2 moles of aluminum nitrate?
there are two moles produced in potassium nitrate.
