The answer is 3,375 moles oxygen.
Four moles of potassium chlorate are needed.
We need 3 moles of potassium perchlorate.
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
2CsClO4 -> 2Cs + Cl2 + 4O2 2.7 moles O2 (2 moles CsClO4/4 mole O2) = 1.4 mole CsClO4 needed
24 mols of aluminum must have reacted since aluminum oxide is Al2O3
4.67
2Cl2 + 7O2 --> 2Cl2O7So for every 2 moles of dichlorine heptoxide formed, 7 moles of oxygen are reacted.69.1 moles Cl2O7 * (7 moles O2 / 2 moles Cl2O7) = 241.85 moles O2
Sounds like an acid metal reaction to produce hydrogen gas, so I will assume you meant hydrochloric acid. Complete reaction indicates aluminum is limiting and drives the reaction. 2Al + 6HCl --> 2AlCl3 + 3H2 3.0 moles Al (3 moles H2/2 moles Al) = 4.5 mole hydrogen gas produced =========================
We need 3 moles of potassium perchlorate.
Four moles of potassium chlorate are needed.
Sulfur dioxide is SO2, so there are 2 moles of oxygen for each mole of sulfur. In 25 moles of SO2, there are 25 moles of S, so there must be 50 moles of oxygen, or 25 moles of diatomic oxygen gas (O2).
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
2CsClO4 -> 2Cs + Cl2 + 4O2 2.7 moles O2 (2 moles CsClO4/4 mole O2) = 1.4 mole CsClO4 needed
3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O is the equation if it is dilute nitric acid. In concentrated nitric acid the equation is different. So 3 moles of copper produce 2 moles of NO. Therefore it requires 6 moles of copper to produce 4 moles of NO.
24 mols of aluminum must have reacted since aluminum oxide is Al2O3