50 g potassium iodide is equivalent to 0,3 moles.
0.02 moles of beryllium iodide is equal to 5,256 g.
530,3 g potassium iodide are needed.
0.02 moles of beryllium diiodide = 5,256 grams
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
224 grams of oxygen are in 2 moles of potassium dichromate.
34,7 moles of potassium 1 356,7 g.
The formula for potassium dichromate is KËÃCrËÃOËÈ. How many grams of oxygen will be in 2 moles of potassium dichromate?
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
Atomic mass of potassium, K = 39.1 Amount of potassium is 156.4g sample = 156.4/39.1 = 4.00mol There are 4 moles of potassium in 156.4 grams of potassium.
3.3 moles of potassium sulfide is equal to 363,86 g.
There are 39.0983 grams in one mole of K (potassium). a mole is a number. you cannot ask how many moles are in potassium. but you may ask how many moles of a certain substance are in potassium.
224 g are in two moles of potassium dichromate.
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
50 g potassium chloride is equivalent to 0,67 moles.
45/94.2 is 0.4777 moles
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
Chemical formula for potassium iodide is KI. Its formula mass is 39.1+127.0=166.1 Amount of KI in 100.0g sample = 100.0/166.1 = 0.602mol
Potassium iodide (KI) has two atoms: potassium and iodine.
The molar mass of potassium is 39,0983(1) g.
There is one atom of potassium in a unit of potassium iodide.
This mass is 347,67 for KMnO4.
1,5 moles of potassium carbonate have 276,41 g.
Potassium has atomic number 39.1.Amount of K in 284g sample = 284/39.1 = 7.26molThere are 7.26 moles of potassium in a 284g sample.
The answer is 224,24 g oxygen.