The answer is 6,31 moles Ag.
How many atoms are present in a piece of sterlingsilver jewelry weighing 33.14 ? (Sterling silver is a silver-copper alloy containing 92.5% by mass.)
The total mass of all the silver atoms would be 10,770,65(47+60) + 35(47+62) = 10,770 The total number of silver atoms is 100, 65 + 35 = 100 Dividing the total mass by the number of atoms gives us a 10770/100 = 107.7 for an atomic mass by these numbers.
A sample of 3,2x10 atoms of nickel is equal to 0,53.10e-23 moles.
200
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
Approx. 9.1024 atoms.
1.7-10^24
How many atoms are present in a piece of sterlingsilver jewelry weighing 33.14 ? (Sterling silver is a silver-copper alloy containing 92.5% by mass.)
Just silver. Silver is an element, so by definition, it's only composed on one type of atom - silver atoms.
Bromine is an element, and no other kinds of atoms or elements are present with it, in a pure sample.
Carbon-13 make up 1.1% of carbon atoms. .011 x 19000 carbon atoms = 209 carbon-13 atoms present.
0.84 lb silver (454 grams/1 lb)(1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) = 2.1 X 10^24 atoms of silver
The total mass of all the silver atoms would be 10,770,65(47+60) + 35(47+62) = 10,770 The total number of silver atoms is 100, 65 + 35 = 100 Dividing the total mass by the number of atoms gives us a 10770/100 = 107.7 for an atomic mass by these numbers.
A sample of 3,2x10 atoms of nickel is equal to 0,53.10e-23 moles.
1
200
They are identical.