This solution contain 0,3 mol of sodium chloride.
0.1 Moles
2.27
There are 10 moles present in 585 g of sodium chloride.
.73 moles
Molarity is moles/liter, so in order to find the moles of a substance in a given volume, simply multiply molarity with volume (in liters). n=M*V
The answer is 2,4 moles.
200/1000 x 6 = 1.2 moles
0,40 moles of sodium chloride contain 23,376 g.
0.1 Moles
2.27
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
The answer is 0,175 moles.
There are 10 moles present in 585 g of sodium chloride.
23.3772 grams are there in four tenths moles of sodium chloride
3.6
Molarity = moles of solute/Liters of solution ( find the moles ) 2.36 M NaCl = moles NaCl/5.08 Liters NaCl = 12.0 moles
This depends on the concentration of sodium chloride in water.