4Na+O2==2Na2o is the reaction. 5 moles of Na2O will form by reacting.
3,33 moles of sodium oxide are obtained.
3,5 moles of sodium oxide will be produced when 10 moles of sodium reacts with oxygen.
The reaction equation is 2 Na + O2 -> Na2O. this shows that each mole of sodium oxide requires two moles of sodium. Therefore, 5 moles of sodium oxide will be produced by reacting 10 moles of sodium.
5 moles:10 Na + (enough) O2 --> 5 Na2O
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
8,55 moles of oxygen are produced.
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
The reaction is:2 KClO3 = 2 KCl + 3 O238,4 moles of oxygen are produced.
Four moles of sodium plus 1 mole of oxygen gas produces 2 moles sodium oxide. 4Na + O2 --->2Na2O
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
Sodium reacts with water. 0.652 NaOH moles will form.
The anwer is 0,061 moles of oxygen.
Potassium chlorate = KClO3Decompostion: 2KClO3 ==> 3O2 + 2KCl7.5 moles KClO3 x 3 mole O2/2 moles KClO3 = 11.25 moles O2
0,028 moles carbonic are obtained.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
The reaction requires 2 moles of hydrogen gas and 1 mole of oxygen gas to produce 2 moles of water.
5C +5O2 ----> 5CO2 So 5 moles of carbon dioxide are produced from 5 moles of oxygen - if there is plenty of carbon and it is not the limiting ingredient.
Na2CO32 * 2 = 4 moles sodium.===========================
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
The equation for the reaction is 4 Na + O2 -> 2 Na2O. This shows that, for complete reaction, one mole of oxygen is required for each four gram atomic masses of sodium. The gram atomic mass of sodium is 22.9898; therefore, 46 grams of sodium constitutes 2.00 moles of sodium, to more than the justified number of significant digits. The gram molecular mass of diatomic oxygen is 31.9988; therefore 160 grams of oxygen constitutes 5.000 moles of diatomic oxygen, to more than the justified number of significant digits. This is well over the minimum amount of oxygen required for complete reaction of all the sodium present. Each two gram atomic masses of sodium produces one gram formula mass of sodium oxide; therefore, the number of gram formula masses of sodium oxide produced is 1.00, to at least the justified number of significant digits.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
10.0 moles oxygen is 10.0 moles oxygen
None. You need Oxygen to form water, not just Hydrogen.
2H2 + O2 -> 2H2O Therefore, 12.0 moles of water.
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