Al2 SO4(wrong) this is how it should be written Al2(SO4)3
This how you do it
3.5 moles Al2(SO4)3 x 3 mole Sulfur / 1 moles Al2(SO4)3 = put that in ur calculator it will give u the answer
how many moles of sulfur are present in 3.4 moles of Al2(SO4)3
Moles = Mass/ Relative Molecular Mass Aluminum forms Al2 compounds, so the relative molecular mass is 2 * 13 = 26. 856/26 = 32.9 (3sf)
Aluminum sulfate Al2(SO4)3 will form when aluminum reacts with sulfur in the presence of oxygen.
First of all, your formula cannot be right. There is no way the formula is Al2S2O33. Sorry, not happening. Maybe it is supposed to be Al2S2O3? But you need to know the actual formula to answer this question.Step 1) Once you have the correct formula, determine the molecular weight of this compound. See the Related Questions link to the left for how to do that.Step 2) Then convert the 25.6 grams of whatever this stuff is into moles. See the Related Questions links to the left for how to convert grams into moles.Step 3) Then based on the formula (as it is now), there are 2 atoms of sulfur for every molecule of this stuff. That means however many molecules you calculated in Step 2 above, you have twice as many moles of sulfur.Step 4) Then convert from moles to atoms. To do that multiply by Avogadro's number and see the Related Questions links for how to do that!
Depending on the formula of the chemical compound containing aluminium.
how many moles of sulfur are present in 3.4 moles of Al2(SO4)3
5,7 moles (SO4)3-.
Moles = Mass/ Relative Molecular Mass Aluminum forms Al2 compounds, so the relative molecular mass is 2 * 13 = 26. 856/26 = 32.9 (3sf)
How many moles are in 4.70g of NH3?
Aluminum sulfate has the chemical formula Al2(SO4)3, so the elements present would be aluminum (Al), sulfur (S) and oxygen (O).
Aluminum sulfate Al2(SO4)3 will form when aluminum reacts with sulfur in the presence of oxygen.
Aluminum Sulfate is Al2 SO4 (aluminum, sulfur, and oxygen)
Al2(CrO4)3 0.92 moles Al2(CrO4)3 (374.98 grams/1 mole Al2(CrO4)3) = 345 grams Al2(CrO4)3 ( might call it 350 grams for sigi figi reasons )
Aluminium sulfate is Al2(SO4)3 and has two aluminium, three sulphates and 12 oxygens. So there are a total of 17 atoms.
Well...Since Aluminum is insoluble in water as an element I assume you mean that an 0.12 mol Aluminum ions react with 0.12 mol Sulfate ions to form x mol of Aluminum Sulfate. Balanced equation (Kinda since since the other portions of the compounds are unknown): 2 Al3+(aq) + 3 SO42-(aq) <----->Al2(SO4)3 (aq) 0.12mol*(1mol Al2(SO4)3 (aq)/2mol Al3+)=0.06mol Al2(SO4)3 (aq) 0.12mol*(1molAl2(SO4)3/3mol SO42-) =0.04mol Al2(SO4)3 (aq) *Answer*
The chemical formula of aluminum sulfate is Al2(SO4)3, consequently this compound contain aluminum, sulfur and oxygen.
Aluminum carbonate is Al2(CO3)3. If you have 7.0x1022 particles of it, then that's 7.0x1022/6.02x1023 = 0.116 moles. The compound has a molar mass of 234g/mol, so 234x0.116=27.144 grams.