0.0002 mol NaCl/mL
molarity = (moles solute)/(L of solution)
0.20 M NaCl = 0.20 mol NaCl/L
1 L = 1000 mL
0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
Molarity = moles of solute/Liters of solution ( find the moles ) 2.36 M NaCl = moles NaCl/5.08 Liters NaCl = 12.0 moles
Molarity = moles of solute/Liters of solutionMoles of solute = Liters of solution * Molarity ( 100 mL = 0.1 Liters )Moles of NaCl = 0.1 Liters * 0.20 M NaCl= 0.02 moles NaCl============
Molarity = moles of solute/liters of solution ( 50 ml = 0.05 liters ) 2.50 Molar NaCl = moles NaCl/0.05 liters solution = 0.125 moles NaCl ( 7.305 grams NaCl )
Molarity = moles of solute/volume of solution. 1 liter = 1000 millilitetrs 3.00M = X Moles/1000ml = 3000 millimoles, or 3 moles NaCl 3 moles NaCl (58.44g NaCl/1mol NaCl ) = 175.32 grams needed. About 4/10 of a pound of salt.
volume given =27.5mlmolarity of base=0.105find number of moles=moles=vol(cm3)/1000*molarity of NaClmoles=27.5/1000*0.105=3.82 moles of sodium chloride
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
The answer is 0,96 moles.
200 mL is 0.200 L and 0.90 M means 0.90 moles/L So, 0.200 L x 0.90 moles/L = 0.18 moles
[2.17/1000]*17.33=0.037mol
1 mole NaCl = 58.443g NaCl 234g NaCl x 1mol NaCl/58.443g NaCl = 4.00 moles NaCl
1 gram NaCl (1 mole NaCl/58.44 grams) = 0.0171 moles NaCl Molarity = moles of solute/volume ( liters) of solution 0.171 M = 0.0171 moles NaCl/volume 0.1 Liters, or more to our point; 100 milliliters