1mole NaCl = 58.443g
20.0g NaCl x 1mol/58.443g = 0.342mol NaCl
11.5 g of Na times x (1 mole of Na/22.99 g of Na) = 0.500 mol of Na I suppose the conversion factor would be what's in parenthesis.
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
Sodium Sulfate is Na2SO4 and the molecular weight is 142. So 0.15 moles would have a mass of 0.15 x142 = 21.3g.
Well the recommended amount of sodium to take per day is not more than 2300mg. So that is 2.3 grams. The atomic mass of sodium is 23.0. So the amount of sodium in moles would be 2.3/23.0 = 0.1moles
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
one mole sodium carbonate contains 23X2 sodium, for three moles it will be 23X2X3=138 gram;
You get salt at the bottom of the pan!
1 mole of Sodium Chloride weighs 58.5 grams (1 mole is the same as the molecular weight of a compound. The molecular mass of Sodium Chloride- NaCl is 23 [Na atomic mass] + 35.5 [Cl atomic mass] which is equal to 58.5 grams).Thus 10 moles would weigh 10x58.5 grams = 585 grams.The answer is 585 grams.
The sodium chloride mass needed is 292,2 g
23 grams of Na is close enough to 1 mole not to matter, so add 35.45 grams of Chloride ion to the flask.
0.720940834 grams
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
11.5 g of Na times x (1 mole of Na/22.99 g of Na) = 0.500 mol of Na I suppose the conversion factor would be what's in parenthesis.
The atomic or ionic mass of sodium is 22.99, and the atomic or ionic mass of chlorine is 35.45. A formula unit of sodium chloride contain one ion of each. Therefore, the mass ratio between sodium and chlorine in sodium chloride is 0.649. The mass ratio between 46 and 70 is 0.657. Therefore, chloride is the limiting reactant in this pair. The mass ratio of chloride to sodium chloride is 35.54/(22.99 + 35.54) or 0.607. Therefore, the mass of sodium chloride formed will be 70/(0.607) or 115 gm, where the depressed last digit indicates that it may not be accurate to + 1. (The limiting datum, 70, has only two significant digits.)
75 g sodium chloride in 150 mL water is a supersaturated solution.
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH