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A cube has 8 non-coplanar points at the vertices and has 6 faces. This is only a partial answer...3 points determine a plane so there will be many more than 6. Your answer is going to be found by the formula n!/(n-r)! where n=8 and r=3.

That gives: 40320/120 = 336

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Q: How many planes are determined by 8 noncoplanar points?
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Related questions

How many planes are determined by 5 noncoplanar points 3 of which are collinear?

3


How many planes are determined by 5 points three are not collinear?

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How many planes are determined by three distinct points that are not on the same line?

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How many different planes are determined by three noncollinear points?

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Points A B and C are noncollinear How many planes can be determined by A B and C?

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How many planes can be determined by A B and C?

If points A, B, and C are not on the same line, they determine a single plane.


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1 line cause every plane contains atleast 3 or more noncollinear points


How many planes can be determined if the point noncollinear?

The answer depends on the number of point. One point - as the question states - cannot be non-collinear. Any two points are always collinear. But three or more points will define a plane. If four points are non-coplanar, they will define four planes (as in a tetrahedron).


How many planes can contain two given points?

If 2 points determine a line, then a line contains infinitely many planes.


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Infinitely many planes may contain the same three collinear points if the planes all intersect at the same line.