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Normally, the height of a cuboid room has no relevance to its square footage. It is, therefore, assumed that the size, given as 4' x 6' x 8' are the side lengths of a triangular room. Then, its area is approx 11.62 square feet.
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What is the size of a one carat sapphire?
5 to 5.5 mm round, 6x4 mm oval , varies depending on cut , this is approximate.
Which molecule obey the octet rule?
Yes, it obeys the octet rule.(Of coarse not an octet for the H atoms: they are saturated with a duplet (=2)).To show you HOW this is done, you will need the structural formula:If it is a monosaccharide there are already 32 different isomeres.And even one of these and the most common one: alpha-D-gluco-pyranose (which is glucose) is too difficultto draw it in this simple 'html-text editor' layout.Just as example some explaining calculation about electron bonding pairs and free pairs.Valence electrons counting:6 C = 6x4 = 24 e12 H = 12x2 = 24 e6 O = 6x6 = 36 eTotal of 84 electrons are available for free or covalent (= bonding) electron pairs(total 84/2 = 42 pairs can be formed)Needed for octets and H-duplets6 C = 6x8 = 48 e6 O = 6x8 = 48 e12 H = 12x2 = 24 eTotal needed for octets/duplets = 120. These are 60 'needed to see' pairsC has no free pairs, all 4 are covalent pairs (= 1 octet): 6x4 = 24 covalent bondsO has 2 free and 2 covalent pairs (= 1 octet): 6x2 = 12 covalent bondsH has no free pairs and 1 covalent pair (= 1 duplet): 12x1 = 12 covalent bonds Total of 24 double counted bonding pairs (48 pairs 'seen' from one atom AND 'seen' from the other atom bound to it, called covalent*) electron pairs)One possible structure (which is not glucose) fitting the above calculation (1, 2, 3) is described here:6 C atoms in a regular (bee hive) ring: 6 covalent pairs6 H atoms directly to each C: 6 cov. pairs6 O atom bonded at one side to each C atom: 6 cov. pairs6 H atoms bonded to the other side of those 6 O atoms: 6 cov. pairsTotal of 24 double counted bonding pairs*) between all atoms.This leaves 6x2 = 12 free electron pairs, two per O atom to fulfill their 'octet need'And now you can conclude:24 double counted = 48 'seen' electron pairs which are covalent*)12 free electron pairs (2 on each O atom)Total of 60 'structural drawn' pairs,Thus this, being the same as the 'needed to see' pairs (60, see above), means that ALL atoms are obeying the octet(+ duplet) rule.*) covalent means: 'seen by two' atoms which are bound together.(The name of this formula would be 1,2,3,4,5,6-cyclo-hexane-hexa-ol, it isn't even a monosaccharide)
How many square feet are there in a room that measures 4 feet by 6 feet?
twenty-four sq. ft. (6x4=24!!!)
How many square feet are in a room that measures 9x7 and another room10x8 and another room 12x 15 and another room 6x4?
Width X Length = Area 9 x 7 = 63 square feet 10 x 8 = 80 square feet 12 x 15 = 180 square feet 6 x 4 = 24 square feet
How many square feet in 6x4 feet?
You need to multiply the two numbers to get the square footage. In this problem the results will be 24 square feet.
How many feet is 6x4?
About 4 walls
How many square meters have you got 6x4 square meter?
6*4 = 24 square metres.
What is the square root of 36x to the 8th power?
The square root of (36x)8 = (36x)4 The square root of 36x8 = 6x4
How many pennies fit in 6x4 jar?
1500 to 2000 US cents will fit into a 6x4 jar.
What qeuls 6x4?
6x4=24
What is the perimeter of a square with 6-inch sides?
Perimeter = 4*6 = 24 inches
How many times does 5 centimeters go into a 6x4 space?
You need to distinguish between linear ( 5 centimetres) and area (6x4 space)
What is the perimeter of a square if it has a area 36 centimetre?
6x6=36 Since there are 4 sides 6x4=24 the perimeter is 24
How do you find the root of a monomial that is a perfect square?
Find the square root of each of its components, and muliply them together. For example, 36x8 the square root of 36 is 6 the square root of x8 is x4 so the square root of 36x8 is 6x4
