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How many times does the prime factor 2 appear in the factorization of 130?
Wiki User
∙ 11y ago
You can find the prime factorization of 130:
130 = 2*5*13
Therefore the answer is 1.
Or you can skip a step. Just divide 130 by 2. You get 65, which is an odd number. Therefore there is only 1 factor of 2 in the factorization of 130.
Wiki User
∙ 11y ago
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How can you tell the number of prime factors a number has when its prime factorization is written in exponent form?
. For example, the factorization of 120 is 23 x 3 x 5, meaning 2 is a factor three times and 3 and 5 are each a factor one time for a total of five prime factors.
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How many times does the prime factor 2 appear in 130?
You can just divide 130 by 2 and get 65, which is odd so it doesn't have 2 as a factor. Therefore the answer is 1.Answer 1You need to find the prime factorization of 130. 130 = 2*5*13Therefore the answer is 1.
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In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.In the prime factorisation of the number, each factor must appear an even number of times.
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How can you tell the number of prime factors a number has when its prime factorization is written in exponent form?
. For example, the factorization of 120 is 23 x 3 x 5, meaning 2 is a factor three times and 3 and 5 are each a factor one time for a total of five prime factors.
