Since a cube has 6 sides, you have a 4 in 6 chance of getting a number less than 5 each time you roll the dice. You would take how many times you want to roll it (360), divide it by the number of sides (6), and multiply it by 4 since you know you have a 4 in 6 chance. So it should be 240. This is strictly mathematical though and you should not consider it accurate since there are many variables when rolling it.
The expected number of rolls under 3 is the number of rolls times the probability of rolling less than 3. So: E(rolls less than 3 out of 30) = 30 * 1/3 = 30/3 = 10
2x = <4
The # of liters would be less.
1
Nine less than five times a number is equal to -30
6
The expected number of rolls under 3 is the number of rolls times the probability of rolling less than 3. So: E(rolls less than 3 out of 30) = 30 * 1/3 = 30/3 = 10
less deuterium
If seven times a number results in 35, then six times a number would be five less.
Less. The more times the coin is tossed, the more likely it will reflect the actual odds of .5 heads and .5 tails.
4n-5 (Which is four times a number minus 5)
Any number less than 3.
I have to assume that you include 5 in your question then there are 6 sides and you can only win on 3 (1/3/5 ) or 3/6 which is 50% probability.
six less than fourteen times a number
13 less than 4 times a number 13 less than is "-13" 4 times a number is "4x" 4x-13■
less
2x = <4