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The grade of the ore from which gold is to be recovered will determine how much of it must be processed to recover that ounce of gold. There is a broad variation, but there is plenty of gold in ores that is dispersed so widely that it is not economical to attempt commercial recovery. In an additional note, gold exists in veins within ores, and is not chemically combined with other elements within that ore. Mines that are probably considered marginal yield something on the order of 4 to 6 grams of gold per ton of ore, and you can do some simple math from there (perhaps using 5 grams/ton) to discover an answer for the stated grade of ore. There are just over 30 grams in a Troy ounce, and at 5 grams/ton, you're looking at 30 divided by 5 or 6 tons of ore to recover that (Troy) ounce of gold from ore with a grade of 5 grams/ton. If you have 6 tons of ore, that's a lot of ore, and you have a lot of hard work ahead of you if want the ounce of gold disbursed in it. It will take time and energy to win the metal, and it might be as cheap to buy the gold as to recover it from the ore. But we'll leave it for you to do the math after you get an assay.

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Q: How many tons of ore contain one ounce of gold?

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1 ounce = 3.12500 × 10-5 short tons

0.00003125

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1/32,000

1 ounce = 3.12500 × 10-5 short tons

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0.00003125 tons is in one ounce 1ton = 2000 lbs 1 lbs=16 ounces so multiply 16x2000 you get 32000 divide 1/32000 and you get how many tons are in one ounce which is 0.00003125

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With gold selling in 2012 at $1700 an ounce or more, a trillion dollars worth would be equal to or less than 29,781 short tons (US). A short ton is 2000 pounds (avoirdupois). A troy pound of gold is 12 troy ounces, and is equal to about 0.823 pounds. At $1700 an ounce (troy), gold would be $20,400 a troy pound, or $16,789 a pound (avoirdupois). A ton would therefore be $33,578,000.

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