Moles of glucose = 80g/180g/mol = 0.444 mole
Molarity = 0.444/0.75L = 0.5926 M
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
The molarity of KNO3 is 0,058.
The molarity of a solution made by dissolving 23,4 g of sodium sulphate in enough water to make up a 125 mL solution is 1,318.
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 40.0mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Molarity=Moles of solute/Liters of solution1.350 g KOH = 0.02406 mol KOH0.02406 mol/0.2500 L =0.09624 M of KOH
The question, as worded, is a little ambiguous. Rather, the question you should be asking is “What is the molarity of a 125 ml aqueous solution containing 10.0g of acetone?” Acetone is roughly 58 grams per mole. Therefore, a 125 mil solution with 10 g of acetone would contain roughly 0.17 moles, and the molarity would be roughly 1.4See the Related Questions for more information about how to calculate the molarity of a solution
Get moles sodium sulfate first.15.5 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.1091 moles Na2SO4Now,Molarity = moles of solute/ Liters of solution ( 35 ml = 0.035 Liters )Molarity = 0.1091 moles Na2SO4/0.035 Liters= 3.1 M Na2SO4 solution==================
Moles of solute ---------------- Liters of solution So, convert your grams to moles by dividing by the molar mass (add together the atomic masses of the solution) and then that will give you your moles. Divide that number by your 6.3 Liters. That number is your molarity.
the body need more energy to produce movement during vigorously exercises,but the oxygen intake is not fast enough to supply oxygen to glucose for producing energy. Glucose, C6H12O6 is break down directly to lactic acid and provide energy. Equation : C6H12O6 ---> 2C3H6O3 + energy
Molarity (concentration ) = moles of solute/Liters of solution 250.0 ml = 0.250 liters 2.431 grams H2C2O4 * 2H2O ( 1mole cpd/ 126.068 grams) = 0.01928 moles H2C2O4 * 2H2O Molarity = 0.01928 moles cpd/0.250 liters = 0.07712 Molarity
the molarity is found by: 19.52g/770mL x 1 mole/156.7g x 1000mL/1L=0.618 mole i got 156.7g by using the chemical makeup of the solution SnF2: Sn's atomic number being 118.7 and rounding F's atomic number to 19.
Molarity = moles solute/liter solutionmoles solute = 7 g NaCl x 1 mol NaCl/58 g NaCl = 0.12 moles NaClliters of solution = 450.0 ml x 1 L/1000 ml = 0.450 litersmolarity = 0.12 moles/0.450 liters = 0.268 M = 0.3 M (one sig fig)
molarity = no. of moles of solute/liter of solution no. of moles of I2 = mass in grams/molar mass = 4.65/253.81 = 0.01832 mol M = 0.01832 mol/0.235 L = 0.0780 mol/L
2.0 mol NaCl / 2.0 Litre = 2.0/2.0 = 1.0 mol/L = 1.0M NaCl
The molarity is 0.001255. Should you really be asking an AP Chem question on Wiki Answers, anyways?
C6H12O6 is the empirical formula for a bunch of carbohydrate compounds. The empirical formula isn't enough to tell you exactly what substance it is; for that you'd need the structural formula, which shows exactly which atoms go where in the molecule. However C6H12O6 compounds do include ordinary glucose and if the question is related to high-school science homework, then that is probably what it's intended to mean.
[117(g NaCl) / 58.5(g NaCl/mol NaCl)] / 40.0(L solution) = [117/58.5]/40.0 = 2.00(mol NaCl) / 40.0(L) = 0.0500 mol NaCl / L solution = 0.0500 M
80 gNaOH / 500 mL = (80 gNaOH / 40 gNaOH/molNaOH) / 0.500 L = 2.0 mol / 0.500 L = 4.0 mol/L
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
burning something, for example glucose. C6H12O6 + 6O2 --> 6CO2 + 6H2O With almost every burning of C (with enough oxigen around), CO2 will be created. (with to little O2 around, you could get CO instead of CO2). In your body the burning of glucose works a bit different.
Glucose is a sugar used by your body as energy. Glucose syrup has enough water added to the glucose to make a syrup.
Molarity = moles of solute / total volume of solution (L or dm3) Moles LiBr = 97.7 g / (6.94 + 79.9) g mol-1 =1.13 mol M = n / V = 1.13 mol / 0.7500 L = 1.50 M There are only three significant figures in the mass of the solute but four in the volume, therefore, answer can not be more than three significant figures.
H + and NO3 - are one to one, so no ratio needed here.Molarity = moles of solute/Liters of solution (500.0 mL = 0.5 Liters)M = 0.30 moles HNO3/0.5 L= 0.60 M H + ions in solution===================