How many nitrogen atoms are in CaNO33?

Answer 1

Ca(NO3)2

Number of atoms in the compound:

Ca- 1

N- 2

O- 6

Find the atomic masses of all atoms and add:

Ca = 40.1

N = 2 * 14.0 = 28.0

O = 6 * 16.0 = 96.0

___________________

164.1 g

Equation:

# moles * added Atomic Mass = # grams

Answer:

4.2 moles * (164.1 g) = 689.22 grams of Ca(NO3)2

Answer 2

This is one mole of Ca(NO3)2. It contains 1 mole of Ca2+ and 1 mole of NO3-

You may be trying to calculate the atoms, molecules, or the molar mass (g/mol)

One mole NO3- ions =6.02* 1023 NO3- ions (Avagadros Number)

Answer 3

I think what you mean to ask is how many grams are in a mole of calcium nitrate, Ca(NO3)2. To do that, grab a Periodic Table and look up the atomic masses for the three constituent elements - calcium, nitrogen, and oxygen - then total them up. 1 calcium, 2 nitrogens, and 6 oxygen = 1(40)+2(14)+6(16)=164 grams/mole.

Now, if you're given a certain mass of calcium nitrate and you want to know how many moles you have, then you would set up a direct proportion with that figure of 164g/mol.

Answer 4

4 grams of Ca(NO3)2 - anhydrous - contain 0,0244 moles.

Answer 5

Ca(NO3)3

This formula is saying one Ca atom and three NO3 compounds or:

Ca NO3 NO3 NO3

3 Nitrogen atoms

Answer 6

6 moles