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EXAMPLE: A certain 100-watt bulb emits a total luminous flux of 1200 lm, distributed uniformly over a hemisphere. Find the illuminance and the luminous intensity at a distance of 1 m, and at 5 m.

SOLUTION: The area of a half-sphere of radius 1 m is

(2[pi])(1 m)² = 6.28 m²

The illuminance at 1 m is

E = 1200 lm ÷ 6.28 m² = 191 lm/m² = 191 lux

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13y ago
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14y ago

E = P.t

E = energy (joules)
p = power (watt)
t = time (seconds)


and watt means number of joules per second


therefore, energy = 100.1 = 100 j/s

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10y ago

"Electricity" is a word that can not be quantifed so you can't ask how much there is. But it is possible to measure electric current (amps), voltage (volts) and power (watts) and even also electrical energy (watt-seconds or kilowatt-hours). A hundred-watt bulb uses 100 watts of electric power and if shining for ten hours it uses 1 kilowatt-hour of energy.

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14y ago

Its equal to Fourquadrillion.True my friends!!!!!!!!!!!!!!

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11y ago

it depends what type genius, if it's a 100 watt bulb then its watt is 100.

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11y ago

It produces about 1200 lumens, about the same as a 20 watt CFL bulb.

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11y ago

It depends on how close you place them. right next to your eyeball and you'll need just one.

If they were all out at the suns distance, then it would be in the region of 3.8 x 1024

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12y ago

Wikipedia states the Sun's luminosity as 3.846×1026 watt.

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