change in energy=mass times specific heat times change in temperature.
7,350 joules
0.583 Joules.
0.237 J/gC is the specific heat of silver matching the Celsius unit, so, since there are two Celsius units to convert, or one mass unit to convert, I will convert kg to g.
q(Joules) = mass * specific heat * delta temp.
10 kg silver (1000 grams/1 kilogram)
= 10000 grams silver ( a lot! )
q = (10000 g Ag)(0.237 J/gC)(35 C - 21 C)
q = 33,180 Joules
----------------------------( 3.3 X 10^4 Joules to be significant figure correct )
The specific heat of silver is 0.233 J/degree/gram
Q = Cg x delta T x mass
= 0.233 x 14 x 10 000
= 32620 J
= 32.62 kJ
32.62
Behind
Jrkk
2,641,760J...
The 10 kg of water. This is because the Specific Heat Capacity for water is 9x larger than Iron. The SHC for water is that it takes 1 calorie of water to raise 1 gram by 1 degrees celsius (1C/1gram X 1 degrees celsius) for Iron it takes 0.11 Calories to raise 1 gram by 1 degrees celsius. Therefore meaning since Water has a higher Specific Heat Capacity, it'll take longer to cool down. Just as it requires a large amount of heat to raise the temperature by 1 degrees Celsius, it requires a large amount of heat to drop the temperature by 1 degrres Celsius. - Ataa Ghomashchi
to solve this we use the formula Q(heat) = mc(change in temp) so, Q=(10g)(4.19J/gC)(18-22) Q=-167.6kJ of heat.
q=mass * Cs * delta T = 0.25kg * 4.18 * (85-10) =78J
If you leave water alone, it is in liquid form. If you raise the temperature of water to boiling, it creates steam. Is this a gas? If you lower the temperature to freezing, it becomes a solid.
3.50 J
115.2
15.37684 joules
mmmm enthalpy
1935 J (apex)
The number of calories required will depend on the mass of water which is to be heated.
10-12
15480.80
The answer is 53,683 kJ.
12 degrees Celsius
12 degrees Celsius
9.6 MJ