If all 1700 Joules of work get converted into heat, then, of course, you get 1700 Joules of heat.
100 watts
0.131 joules/gram'C x 1.3 grams x (46-25)'C = 3.5763 joules
5 joules
0.385 Joules/Gram Celsius is the specific heat of copper. So, q(Joules) = mass * specific heat * change in temperature q = (200 g Cu)(0.385 J/gC)(30 C - 150 C) = - 9240 Joules -------------------------amount of heat dissipation ( answer can be positive )
pyrometry utilise a electrical device called a pyrometer to measure the amount of heat-- light exuding from a body as a measure of heat/ radiated heat .
Heat generated in a nuclear fusion depends on the resistance of the plasma and the current.
100 watts
Something about 1550 foot pounds, or 2115 joules.
It is measured in joules (J)
About 322.5 Joules of heat
1,000 joules of heat energy for every second that the 1,000 watts' dissipation continues.
0.131 joules/gram'C x 1.3 grams x (46-25)'C = 3.5763 joules
5 joules
The necessary heat is 9,22 joules.
The latent heat of condensation of steam is 2260 Joules per gram (539.3 cals/g). So the amount of heat released by 12.4 g = 12.4*2260 Joules = 28,024 Joules or 6687 cals.
q( in Joules ) = mass * specific heat * change in temperature [ convert temps--Tf = Tc(1.80) + 32 ] q = (40 g)(0.90 J/gC)(61.1o C - 22.8o C) = 1.4 X 103 Joules =============
0.385 Joules/Gram Celsius is the specific heat of copper. So, q(Joules) = mass * specific heat * change in temperature q = (200 g Cu)(0.385 J/gC)(30 C - 150 C) = - 9240 Joules -------------------------amount of heat dissipation ( answer can be positive )