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Multiplication of the values 5.58 kg, 980 °C and 450 j/kg°C yield a result

in joules. This is equal to 2.46 x 106 joules. (This is a large iron weight being heated, but not melted.)

For raising temperature

Q = m*Cp*dT

The specific heat Cp needs to be in units of energy/mass-temperature

The figure is 0.45 J/g°C or 450 J/kg°C

Equation of similar form is melting of metal the equation is

Q= m.Hfusion

The heat of fusion has no temperature scale because it is a phase change without change of temperature. You might be confused between calculation of sensible heat and latent heat.

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13y ago
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7y ago

The specific heat of cast iron is 0,46 kJ/kg.K.
Thr total heat is 2 515kJ.

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Q: How much heat is needed to raise the temperature of 5.58 kilograms of iron from 20 degrees C to 1000 degrees C if the specific heat of iron is 450 joules per kilogram degree C?
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