lf = 3.35 x 105 J kg-1
This much amount of heat required to convert 1 kg of ice to liquid
Mani.Ra
It is the additional amount of heat [measured in (the "big") calories ] required to cause boiling/vaporization of a liquid already at the boiling/vaporization temperature. Heat of vaporization is the amount of heat (540 calories/gram) needed to change a specific amount of liquid (1 gram) at it's boiling point into a gas without changing it's temperature. -Qwasas
heat of fusion is 333.55 (kJ/kg) rephrasing the question to the metric system: How much heat will be required to change 2.27 Kg of ice at 0 degrees into water at 27 degrees? heat of fusion is 333 * 2.27 = 756 kjoules or 756000 joules (melts the ice) specific heat of water (liquid): cp = 4.185 J/gK (this is given in grams, so we have to convert) or cp = 4185 J/kgK multiplying 4185 * 2.27 * 27 = 256,500 joules total = 256,500 + 756000 = 1012500 joules or 241,800 callories or 960 BTU
The answer will depend on the temperature of the liquid water and the pressure.
When you heat the base of a liquid, the particles heat up and rise, as they become less dense. When they reach the top of the container, they cool and sink, as they now become more dense again. When they get to the bottom, the whole process starts again.
molar masse acetone: 58.08 g/mol 43.9g/58.08g/mol =0.75585mol the energy required for vaporization to a gas is... 0.75585molx29.1KJ/mol =21.995KJ
how much heat is required to convert 0,3kg of ice at 0c to water at the same tempture
No heat (energy) is required to freeze water (from liquid to solid). Freezing RELEASES energy (heat), as it is an exothermic event. If you want to know how much energy is release, you need to know the heat of fusion for water, and then multiply that by the mass of water being frozen.
The molar heat of fusion of water in J / g is 334. To find the heat required to convert 0.3 kg, use the equation: heat of fusion * mass = heat required. It would require 100.2 kJ.
Energy is given off when cooling from a liquid to a solid. How much depends on the elements involved and the amount.
question makes no sense.....
7.9
Can you help
Specific heat capacity (equation Q=mc��T) is the measure of the energy required in Joules to raise 1kg of a substance by 1.0 K (numerically equivalent to 1 C)Whereas, specific latent heat (equation Q=mL) is the amount of energy needed to change to the state of a substance either from solid to liquid, liquid to gas without changing its temperature.
19.7 kJ
Heat of vaporization or enthalpy of vaporization. It is the additional energy, per unit mass, required after vaporization temperature (boiling point) is reached, to accomplish the change in state, from liquid to gas.
The energy required to boil a liquid is dependant on what the liquid is, as every liquid has it's own constant known as a specific heat capacity. This essentially boils down (ha ha) to the strength of the bonds between the molecules, which varies depending on the molecule itself. Water for instance has much stronger intermolecular attractions that, say, liquid nitrogen.
The energy required to boil a liquid is dependant on what the liquid is, as every liquid has it's own constant known as a specific heat capacity. This essentially boils down (ha ha) to the strength of the bonds between the molecules, which varies depending on the molecule itself. Water for instance has much stronger intermolecular attractions that, say, liquid nitrogen.