0
How much ozone at what rate and pressure should be added to a swimming pool capacity 625000 liters and circulation of 171000 liters per hour?
Wiki User
∙ 13y ago
Pressure depends on the pool's filtration system pressures. Usually, ozone is drawn in under a vacuum, using an eductor, with the eductor perhaps on a sidestream.
Skimmer -> skimmer pump -> ozone addition -> filter with means to allow ozone offgas exit / destruction -> the rest of the normal pool system.
The ozone dose depends on bather loading, the amount and type of detritus that could fall in the pool. Applied doses of 1 - 2 ppm are not uncommon. More than that is not unknown but may be required.
Pools that use ozone for the sole sterliant I have no experience with, but I expect multiple dosing points, x2 to x5 the amount of ozone, and special piping fittings in the pool.
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
How do you write 171000 in words?
One hundred seventy-one thousand.
What is 5.7 percent of 3 million?
5.7% of 3 million is 171000
A biker in a big race in France averaged 171000 meters a day If he rode 3427.5 kilometers in all then about how many days was he racing?
20 days
What is the GCF of 255 and 1000?
255 = 5 x 51 = 3 x 5 x 171000 = 103 = 23 x 53GCF = 5
What fraction of whole numbers is equal to 17100 and that has a denominator that is a power of 10?
17100 = 17100/1 = 17100/1 × 10/10 = 171000/10 = 17100/1 × 10²/10² = 1710000/100 = 17100/1 × 10³/10³ = 17100000/1000 ... = 17100/1 × 10ⁿ/10ⁿ There is no upper limit to this sequence: n = 0, 1, 2, 3, .... These numbers can be put in a one-to-one relationship with the counting numbers 1, 2, 3, ... The counting numbers can also be put in a one-to-one relationship with the whole numbers Therefore the sequence of fractions can be put in a one-to-one relationship with the whole numbers. Therefore the fraction of whole numbers which are in the sequence is 1. ----------- Let's try another approach: As 10 to some power is positive, there is no way we can change a negative number to make it positive by dividing by 10 to some power, therefore the solution numbers are all positive. As negative whole numbers make up half of the whole numbers, the fraction of whole numbers which are equivalent to 17100 when divided by a power of 10 is at most ½. The fraction of the ½ of the whole numbers which are positive can now be considered: After the nth whole number has been found which matches the criteria that is it equivalent to 17100 when it is divided by a power of 10, in total there are n numbers matching out of a total of 17100 × 10ⁿ⁻³ numbers (the value of the nth number); thus: The first number which meets the criteria is 171/10⁻² → the fraction is 1/171 The second number to meet the criteria is 1710/10⁻¹ → the fraction is 2/1710 The third number to meet the criteria is 17100/10⁰ → the fraction is 3/17100 The fourth number to match the criteria is 171000/10 → the fraction is 4/171000 The fifth number to match the criteria is 1710000/10²→ the fraction is 5/1710000 → For the nth match, the fraction is: n/(17100 × 10ⁿ⁻³) = (1/17100) × n/10ⁿ⁻³ This gives us a sequence of fractions: 1/17100 × 1/10⁻², 1/17100 × 2/10⁻¹, 1/17100 × 3/10⁰, 1/17100 × 4/10¹, 1/17100 × 5/10², ... = 100000/17100000, 20000/17100000, 3000/17100000, 400/17100000, 35/17100000, 6/17100000, .... Consider terms n and n+1: U{n} = (1/17100) × n/10ⁿ⁻³ = (1/17100) × 10 × n/10ⁿ⁻² U{n+1} = (1/17100) × (n+1)/10ⁿ⁻² U{n} - U{n+1} = (1/17100) × 10 × n/10ⁿ⁻² - (1/17100) × (n+1)/10ⁿ⁻² = (10n - (n+1))/(17100 × 10ⁿ⁻²) = (9n - 1)/(17100 × 10ⁿ⁻²) As n ≥ 1, 9n - 1 ≥ 9×1 - 1 = 8 → term n - term n+1 ≥ 8 > 0 → term n is larger than term n+1 for all n ≥ 1 Each of these terms is less than 1, and each term of the sequence is smaller than the previous one and so as n increases the value of the each term (the fraction of whole numbers which meet the criteria) tends towards 0. → The fraction of all whole numbers which equate to 17100 when divided by a power of 10 is as near enough to zero as make no odds. ie the fraction is so small it is effectively none of the whole numbers. ----------------------- This is a problem of dealing with the infinite.
Elgin open face 14K casing 15 jewels aprox 100 yrs old more or less Has number 415249 inside back gold back casing and the number 12892247 on the steel inside inner watch workings plate what is value?
Search Results For "12892247" Serial Number SN Range Quanty Name Year grade size code jewels Adj/reg/etc. -------------- -------- ------ ---- ---- ----- ---- ------ ------ ------------ 12892247 12892001 2000 1906 315 12s o3n3p 15j e grade total runs first yr last yr class size code jewels Adj/name ----- ----- ----- -------- ------- ----- ---- ------ ------ ---------- 315 1033900 329 1903 1939 114 12s o3n3p 15j Class 114: 12s OF 3/4 pend model 3 303 2215000 made 7j 304 13000 made 15j 311 171000 made 7j gilded 315 1033900 made 15j 345 730900 made 17j 364 16700 made 15j gilded 384 177900 made 17j Adj 394 5000 made 7j gilded 1950 MC says "12x16s" dial/hands 396 4400 made 15j gilded 1950 MC says "12x16s" dial/hands 997 2000 made 17j A4P Marked TRN. two tone really a G=345 998 4000 made 17j A4P Marked STR or ELT. really a G=345 "Star burst" damaskeening
