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See the Related Question linked the the left of this answer: = How do you solve an Ideal Gas Law problem? = Note that STP is standard temperature and pressure. Standard pressure is 1 atm, and standard temperature is 0 °C, which is 273.15 Kelvin.

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16y ago
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15y ago

If you know the density of oxygen and the molar mass of oxygen you can divide the two in order to find the molar volume of oxygen. (L/mol) Oxygen has a density of 1.429 g/L and a molar mass of 32.00 g/mol. (Just remember that the molar mass of oxygen, chemical formula of 0 2, comes straight from the Periodic Table.) So, divide: 1.429 g/L / 32.00 g/mol = 22.393 L/mol. The "g" unit cancells out and you're left with L/mol which is your molar mass. Compare that with 22.4 L/mol which is the accepted molar volume for an ideal gas, derived from the ideal gas law: pv=nRt. However, because most gases do not behave ideally there is a slight discrepancy.

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10y ago

Molecular mass of O2 = 2(16.0) = 32.0

Amount of O2 = 16/32.0 = 0.50mol

1 mol of O2 contains 6.02 x 1023 molecules (avogadro constant).

In one O2 molecule there are two O atoms.

Thus, number of atoms present = 2 x 0.50 x 6.02 x 1023 = 6.02 x 1023

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9y ago

16.0 grams of O2 is equal to 0.5 moles, which has a volume of 11.2 liters at STP. 16.0 moles of O2 has a volume of ?æ358 liters.

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13y ago

What is the volume of 1.2 moles of oxygen gas 02 at standard temperature and pressure

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7y ago

The volume is 6,09 mL.

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11y ago

22.4 liters

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Q: How many atoms are present in 16g of oxygen gas?
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What is the mass in grams of 1mole of oxygen?

The mass of 2.000 mol of oxygen atoms is 32.00 grams.


How many oxygen atoms are present in 40.0 grams of oxygen gas?

Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms


How many grams of magnesium are needed to react with 16g of 02?

I assume you mean this reaction. 2Mg + O2 --> 2MgO 16 or 160 ??? Either way the form is the same. We will use the 16 grams. 16 g O2 (1 mole O2/32 grams)(2 mole Mg/1 mole O2) = 1.0 mole magnesium needed ======================


What is the mass of one mole of iron sulphate?

In one mole of each element there is... Fe - 56g O - 16g S - 32g Th equation is Fe2(SO4)3 56g x 2 = 112g 32g x 3 = 96g 16g x 12 = 192g 112g + 96g + 192g = 400g 400g


A 2.086-g sample of a compound contains 0.884 g of cobalt 0.482 g of sulfur and 0.720 g of oxygen What is its simplest formula?

Convert the number of grams given into percentage: 0.884/2.086=42.37% 0.482/2.086=23.1% 0.720/2.086=34.51% Then assume the percentage represent a mass in grams and calculate the amount of moles present in that mass: For Cobalt 42.37g/58.93g/mol= 0.72 mol (simplify units) For Sulphur 23.1g/32.06g/mol= 0.72 mol For Oxygen 34.51g/16g/mol= 2.16 mol Take the numbers of moles obtained and divide it by the smallest value: 0.72/0.72=1 0.72/0.72=1 2.16/0.72= 3 Therefore, the simplest formula is CoSO3

Related questions

How many atoms are present in 16g of O?

The Avogadro number: 6,02214129(27)×1023.


How many atoms in 16g of O and 8g of S?

7,5276766125.1023 atoms.


What is the mass in grams of 1mole of oxygen?

The mass of 2.000 mol of oxygen atoms is 32.00 grams.


If 16g of oxygen contains 1 mole of oxygen atoms calculate the mass of one atom of oxygen in grams?

1


How many atoms are in 16 grams of oxygen?

1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O


How many atoms in 16g of O?

The Avogadro number: 6,02214129(27)×1023.


How many number of moles of carbon dioxide that are contain 16g of oxygen?

As one mole of CO2 contain 2 oxygen having molar mass 32. Soo there will be 0.50 moles of CO2 which contain 16g of oxygen....!


How many oxygen atoms are present in 40.0 grams of oxygen gas?

Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms


What is the atomic mass of Hydrogen Nitrogen and oxygen?

hydrogen-1g nitrogen-14g oxygen-16g


How many moles of atoms are there in 3.968x1023 atoms Mg?

Divide that number by Avogadro's number: 3.968x10(23) / 6.02x10(23) = 0.659mol Mg, which would be about 16g.


How many atoms are present in 16g of O and 8g of S?

16 g O x 1 mol/16 g = 1 mole and 1 mole = 6.02x10^23 atoms of O8g S x 1 mol/32 g = 0..25 moles S and then 0..25 moles x 6.02x10^23 atoms/mole = 1.5x10^23 atoms of S, or rounding to 1 significant figure, you have 2x10^23 atoms of S


How can you tell there is more oxygen in hydrogen peroxide than in water?

In 1 mole of water, the total amount of oxygen is only 16g. But the amount of the same in 1mole of Hydrogen peroxide is 32g. So more oxygen is present in hydrogen peroxide than in water.