See the Related Question linked the the left of this answer: = How do you solve an Ideal Gas Law problem? = Note that STP is standard temperature and pressure. Standard pressure is 1 atm, and standard temperature is 0 °C, which is 273.15 Kelvin.
If you know the density of oxygen and the molar mass of oxygen you can divide the two in order to find the molar volume of oxygen. (L/mol) Oxygen has a density of 1.429 g/L and a molar mass of 32.00 g/mol. (Just remember that the molar mass of oxygen, chemical formula of 0 2, comes straight from the Periodic Table.) So, divide: 1.429 g/L / 32.00 g/mol = 22.393 L/mol. The "g" unit cancells out and you're left with L/mol which is your molar mass. Compare that with 22.4 L/mol which is the accepted molar volume for an ideal gas, derived from the ideal gas law: pv=nRt. However, because most gases do not behave ideally there is a slight discrepancy.
Molecular mass of O2 = 2(16.0) = 32.0
Amount of O2 = 16/32.0 = 0.50mol
1 mol of O2 contains 6.02 x 1023 molecules (avogadro constant).
In one O2 molecule there are two O atoms.
Thus, number of atoms present = 2 x 0.50 x 6.02 x 1023 = 6.02 x 1023
16.0 grams of O2 is equal to 0.5 moles, which has a volume of 11.2 liters at STP. 16.0 moles of O2 has a volume of ?æ358 liters.
What is the volume of 1.2 moles of oxygen gas 02 at standard temperature and pressure
The volume is 6,09 mL.
22.4 liters
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms
I assume you mean this reaction. 2Mg + O2 --> 2MgO 16 or 160 ??? Either way the form is the same. We will use the 16 grams. 16 g O2 (1 mole O2/32 grams)(2 mole Mg/1 mole O2) = 1.0 mole magnesium needed ======================
In one mole of each element there is... Fe - 56g O - 16g S - 32g Th equation is Fe2(SO4)3 56g x 2 = 112g 32g x 3 = 96g 16g x 12 = 192g 112g + 96g + 192g = 400g 400g
Convert the number of grams given into percentage: 0.884/2.086=42.37% 0.482/2.086=23.1% 0.720/2.086=34.51% Then assume the percentage represent a mass in grams and calculate the amount of moles present in that mass: For Cobalt 42.37g/58.93g/mol= 0.72 mol (simplify units) For Sulphur 23.1g/32.06g/mol= 0.72 mol For Oxygen 34.51g/16g/mol= 2.16 mol Take the numbers of moles obtained and divide it by the smallest value: 0.72/0.72=1 0.72/0.72=1 2.16/0.72= 3 Therefore, the simplest formula is CoSO3
The Avogadro number: 6,02214129(27)×1023.
7,5276766125.1023 atoms.
The mass of 2.000 mol of oxygen atoms is 32.00 grams.
1
1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O
The Avogadro number: 6,02214129(27)×1023.
As one mole of CO2 contain 2 oxygen having molar mass 32. Soo there will be 0.50 moles of CO2 which contain 16g of oxygen....!
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms
hydrogen-1g nitrogen-14g oxygen-16g
Divide that number by Avogadro's number: 3.968x10(23) / 6.02x10(23) = 0.659mol Mg, which would be about 16g.
16 g O x 1 mol/16 g = 1 mole and 1 mole = 6.02x10^23 atoms of O8g S x 1 mol/32 g = 0..25 moles S and then 0..25 moles x 6.02x10^23 atoms/mole = 1.5x10^23 atoms of S, or rounding to 1 significant figure, you have 2x10^23 atoms of S
In 1 mole of water, the total amount of oxygen is only 16g. But the amount of the same in 1mole of Hydrogen peroxide is 32g. So more oxygen is present in hydrogen peroxide than in water.