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There are 231 cu.in. in a gallon of water 18'= 216", 33'=396", multiplied together you have 85,539 sq.in. Multiply by the height (in inches) and devide by 231 and you get the gallons in the pool. 3'high=36" 85,539x36= 3,079,296 cu. in. 3,079,296 divided by 231 = 13,330.26 gallons.

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Cannot be answered with only these measurements. You need to specify what shape the pool is. Also, for a rectangular pool, the length, width and depth are needed. For a round pool, the diameter and depth are needed.

18-ft x 33-ft x 4-ft = 2,376 cubic feet = 17,773.7 gallons

That's the volume of the pool. We have no way to know

how much water there may be in it.

Go to http://www.havuz.org/pool-calculators.htm

An above ground pool 18x33 - 4ft deep holds about 14k gallons of water. An 18x33 - 4ft above ground pool has about 14k gallons of water.

Formula for Volume: Length X width X depth X 7.48 = gal

Pool gallonage equation is: L x W x Average Depth X 7.5 = ???? gallons of water

26658.72 gallons

About 22,217 gallons of water.

Q: How much water is in an 18 x 33 foot above ground pool that is 7 ft at its deepest hold?

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It is now illegal to have a five foot and deeper pool.

18,506 U.S. gallons

Just a little over 6,000 gallons.

5300 Gal

18,000

There are 6016.20 gallons of water for every 1 foot of heigth. Therefore, the total gallons is 24,065gallons. Hope this helps. Louis Daigle

Diameter x Diamater X Depth X 5.2

18000

1 foot above the ground.

13,346 gallons per vertical foot.

There are 13,536 gallons in a 24 foot diameter pool that has 4 feet of water. Not true for a pool that is 4 feet in height. This would hold less than 4 feet of water.

We have a 24' foot round above ground with 13000.00 gallons of water and that only requires a 1 hp pump a 2 hp pump may be overkill and cost more to operate