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# How much water is in an 18 x 33 foot above ground pool that is 7 ft at its deepest hold?

Updated: 9/27/2023 Wiki User

15y ago

There are 231 cu.in. in a gallon of water 18'= 216", 33'=396", multiplied together you have 85,539 sq.in. Multiply by the height (in inches) and devide by 231 and you get the gallons in the pool. 3'high=36" 85,539x36= 3,079,296 cu. in. 3,079,296 divided by 231 = 13,330.26 gallons. Wiki User

12y ago   Wiki User

13y ago

Cannot be answered with only these measurements. You need to specify what shape the pool is. Also, for a rectangular pool, the length, width and depth are needed. For a round pool, the diameter and depth are needed.   Wiki User

12y ago

18-ft x 33-ft x 4-ft = 2,376 cubic feet = 17,773.7 gallons

That's the volume of the pool. We have no way to know

how much water there may be in it.   Wiki User

15y ago

Go to http://www.havuz.org/pool-calculators.htm   Wiki User

15y ago

An above ground pool 18x33 - 4ft deep holds about 14k gallons of water. An 18x33 - 4ft above ground pool has about 14k gallons of water.   Wiki User

14y ago

Formula for Volume: Length X width X depth X 7.48 = gal   Wiki User

14y ago

Pool gallonage equation is: L x W x Average Depth X 7.5 = ???? gallons of water   Wiki User

14y ago

26658.72 gallons   Wiki User

13y ago   Earn +20 pts
Q: How much water is in an 18 x 33 foot above ground pool that is 7 ft at its deepest hold?
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