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-log[H+] = pH therefore -log[0.001] = 3.00 The pH of a solution of 0.001 mol dm HC1? is 3.00
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12 dm.12 dm.12 dm.12 dm.
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well depending on the concentration of the solution but heres the equation to work it out: pH= -log[H+] so if the solution was a 1 mol dm^-3 HCl then: pH= -log(1) = 0 Hence 1 mol dm^-3 of HCl is VERY acidic Remember pH:0 is very acidic/ pH:7 in neutral/ and pH:14 is very basic
7m.........dm
Since 1 m = 10 dm, then 1 m 60 dm + 30 dm = 70 dm + 30 dm = 100 dm = 10m or 1 m 60 dm + 30 dm = 1m 90dm = 10 m.
dm = decameter 1 dm = 10 m answer: 50 dm