Depending on power and spectral purity requirements, production of a sinusoidal wave from a DC input can be done with several methods:
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It isn't clear what you are applying the input to. The results may vary, depending on the specific circuit.
There is more than one technique. The most common is to use an electronic switch to convert the DC into a square wave, the square wave is filtered to make it a (rough) sine wave. This can then passed through a transformer to the desired voltage. The advantage of this system is that it is very efficient, the disadvantage is that the sine wave produced isn't all that good a sine wave and some devices (AC motors, for example) sometimes have problems when being powered by inverters. An alternative is to use an oscillator to produce the sine wave. This produces a better sine wave, but is less efficient.
In most circumstances a full wave diode bridge is used to convert AC into DC. Along with inductors and capacitors used as filters, the DC ripple is smoothed out to a very stable DC voltage. This is the method used in DC power supplies. To convert from DC to AC an inverter is used. Today most inverters use the modified sine wave method which brings the sine wave closer to a AC generated sine wave. Older inverters used an on - off switching procedure to generate a square sine wave. Modern electronics do not work well with square wave generation.
A: ANALOGUE IT can be AC or DC it is up to the application involved An analog signal can be a sine wave, a square wave a sawtooth wave or any other varying waveform
Since a sine wave is described by the trigonometric sin(x) function, which is symmetrical, the sine wave is also symmetrical, unless there is a DC bias, in which case it is not. (It depends on your definition of symmetry)
Not really. DC is not a sine wave at all. It is a flat line, in terms of time. On the other hand, if the DC is coming from a power supply that is rectifying AC and filtering it, but not regulating it, then under load conditions, it will exhibit a semi triangular waveform. It will increase when the input AC rises above the diode forward bias point and then it will follow the input AC. It will decrease linearly when the input AC reaches is peak and then starts back down, with a slope proportional to the load. As such, it is a periodic waveform, and by Fourier analysis, it is then a sum of various sine waves. Even if you don't want to get "technical" by looking at Fourier, you can still compare the semi triangular waveform with the input AC waveform, and see that they "fit together". So, yes, 12 volt DC from a power supply is a modified sine wave, unless, of course, there is a regulator stage in the power supply - in that case, it should be flat, as stated first, above.
This DC voltage is called the DC offset. Any decent signal generator will be able to add DC offset to the signal it generates. If you don't have one, simply connect a DC voltage to your signal.
If a sine wave is applied to a rectifier, and the sine wave is strictly AC (no DC offset), the output will be 1/2 the wave - it will be clipped near zero, as the diode prevents reverse voltages. So the output will NOT be a perfect sine wave.
An AC waveform is a sine wave and varies from positive to negative with a frequency of 60 Hertz (Cycles per Second). DC is a constant voltage and does not vary like the sine wave.
it is DC powered, but can generate sawtooth or triangular wave AC if wired up properly. it cannot generate sine wave AC, although with an opamp wave shaping circuit the triangular AC waveform can be reshaped to a rough approximation of a sine wave.
Try the mathematics and you will see how.For f(x) = ∫x dt, where x is a square wave function, f(x) will be a triangle wave function.Also try what happens where x is a triangle wave function!