Using Pythagoras' theorem:
162+122 = 400 and the square root of this is 20 (the diagonal)
Therefore: 16+12+20 = a perimeter of 48 inches
By using Pythagoras it is: 6+8+6+8 = 28 inches
166 inches
1.72666 yards.
By Pythagoras, the other side is 24 inches long. So the perimeter is 2*(10+24) = 2*34 = 68 inches.
If you mean a 3 inches by 4 inches rectangle then its perimeter is 14 inches
By using Pythagoras it is: 6+8+6+8 = 28 inches
The answer is 166 inches.
166 inches
The perimeter of this rectangle is 30 inches.
The length of a rectangle is 8 inches. The width of the rectangle is 4 inches. What is the perimeter of the rectangle in inches?
1.72666 yards.
Whether that's the length, the width, the diagonal, or the perimeter, you don't have enough information. To get the area of a rectangle, you need at least two measurements.
26.4 inches for the diagonal.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
By Pythagoras, the other side is 24 inches long. So the perimeter is 2*(10+24) = 2*34 = 68 inches.
If you mean a 3 inches by 4 inches rectangle then its perimeter is 14 inches
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.