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I need to draw a circuit diagram to show this but I have no idea how do you find the resistance of a lamp in a circuit?
Jules104
If you have a lamp, you can assume that the resistance of the lamp when it is under power will follow the ohms law.
BUT, one thing you must remember is, when a lamp is under load, it is glowing HOT. When metal is HOT, the molculoes of the meals are in much more active state. When this happens, the resistance will increase. Conversely, when the lamp is NOT on ON state, the filaments are cold. Moleculoes in the filaments are not as active. Thus, the resistance is lower. There is almost 10 to 1 difference in resistance from hot to cold.
Taking out a multimeter and measuring the resistance of the lamp will not help you determine the resistance of the lamp when it is actually under load (with voltage applied) Really, the only thing you can do is to measure the voltage, measure the current, then arrive at the resistance mathmatically.
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What is meant by calculate the equivalent resistance of the circuit from the measured potential difference across the battery and the current through the battery is there a formula for this?
In a complex circuit with various elements (resistors, capacitors etc.) and one battery, the various circut elements contribute to draw a certain amount of current "I"from the battery at some terminal voltage "V". The "equivalent" resistance of the various circuit elements is that resistance "R" which will draw the same current , at the same terminal voltage, as the complex circuit. So to find "R" you simply imagine replacing the complex circuit with "R" by attaching "R" across the terminals of the battery and use Ohms law to find "R" , demanding "I" and "V" are the same. So then R = V/I.
How do you find resistance in a circuit?
That entirely depends on whether the resistances are in series or in parallel with each other. Ohm's law states that I=V/R. i.e. current = voltage/resistance. If you know the current and voltage you can find the resistance. You can use algebra to rearrange the formula for R and get that R= V/I. Resistance = voltage/current.
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What is meant by calculate the equivalent resistance of the circuit from the measured potential difference across the battery and the current through the battery is there a formula for this?
In a complex circuit with various elements (resistors, capacitors etc.) and one battery, the various circut elements contribute to draw a certain amount of current "I"from the battery at some terminal voltage "V". The "equivalent" resistance of the various circuit elements is that resistance "R" which will draw the same current , at the same terminal voltage, as the complex circuit. So to find "R" you simply imagine replacing the complex circuit with "R" by attaching "R" across the terminals of the battery and use Ohms law to find "R" , demanding "I" and "V" are the same. So then R = V/I.
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