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Q: If 102030.1000 then n

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n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed

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n+n-n-n-n+n-n-n squared to the 934892547857284579275348975297384579th power times 567896578239657824623786587346378 minus 36757544.545278789789375894789572356757583775389=n solve for n! the answer is 42

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Assuming you mean the first n counting numbers then: let S{n} be the sum; then: S{n} = 1 + 2 + ... + (n-1) + n As addition is commutative, the sum can be reversed to give: S{n} = n + (n-1) + ... + 2 + 1 Now add the two versions together (term by term), giving: S{n} + S{n} = (1 + n) + (2 + (n-1)) + ... + ((n-1) + 2) + (n + 1) → 2S{n} = (n+1) + (n+1) + ... + (n+1) + (n+1) As there were originally n terms, this is (n+1) added n times, giving: 2S{n} = n(n+1) → S{n} = ½n(n+1) The sum of the first n counting numbers is ½n(n+1).

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No. n is not a factor of n + 5.

0000001231 00000 n 0000001568 00000 n 0000001997 00000 n 0000002422 00000 n 0000002646 00000 n 0000003065 00000 n 0000003598 00000 n 0000003958 00000 n 0000004188 00000 n 0000004859 00000 n 0000005089 00000 n 0000005322 00000 n 0000005352 00000 n 0000005393 00000 n 0000005416 00000 n 0000007589 00000 n 0000007612 00000 n 0000009534 00000 n 0000009557 00000 n 0000011430 00000 n 0000011453 00000 n 0000013308 00000 n 0000013331 00000 n 0000015313 00000 n 0000015606 00000 n 0000015762 00000 n 0000015785 00000 n 0000017643 00000 n 0000017666 00000 n 0000019625 00000 n 0000019648 00000 n 0000021567 00000 n 0000030635 00000 n 0000064611 00000 n 0000064818 00000 n 0000064897 00000 n 0000080609 00000 n 0000087276 00000 n 0000087483 00000 n 0000087701 00000 n 0000090379 00000 n 0000001724 00000 n 0000001975 00000 n

N+n=0

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It is a resonance structure with 3 possible Lewis Structures. h-n-n-n n-h-n-n (n-n-h-n is the same thing) n-n-n-h N - 5 Valence Electrons H - 1 (will be used to bond)

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jnknknlnlnl mnn n n n' m m m n n m m m n n ,n n n; nm nm jbjnb