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secA(sinA)=0

(1/cosA)(sinA)=0

tanA=0

Therefore A is in 1st or 3rd Quadrant

i.e A=0 Degrees, 180 Degrees....

This yields cosA=1 or cosA=-1

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13y ago
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Q: If SecASinA equals 0 then what will be the Value of CosA?
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