If a colour blind man married a carrier woman they could produce a carrier daughter, a colour blind daughter, a normal son or a colour blind son. The probability of each phenotype occurring is 25%.
If XC represents the normal allele for seeing colour and Xc represents the colour blind allele the genotypes of the possible offspring would be as follows:
Carrier daughter = XCXc
Colour blind daughter = XcXc
Normal son = XCY
Colour blind son = XcY
This information is incorrect. In fact a woman can be color blind. My mother is color blind as are my brothers. My sister and I are not though we carry the gene. I have two daughters and one is color blind and the other is not color blind.
The information I gave is not incorrect - I have included the possibility of that 'mating' producing a colour blind female child.
color blindness is sex linked and x-chromosomal recessive.
so if a man has has it and a women carries it the cross would be AA x Aa
and the results would be Aa, Aa, AA, AA. so therefore the female would either get it or be a carrier- a 50% chance. and a male would get the colorblindness
0 percent. for the daughter to be colorblind, she needs 2 "blind" alleles. the father will supply a normal allele, but the mother may give her daughter the "blind" allele. If it is a daughter, the chances of being a carrier is 50%, the chance of being normal is 50%. Both scenarios will not cause colorblindness
A very ambigous question, it depends whether the mans's two alleles are dominant, one dominant one recessive, or both recessive. If both dominanat then they will be colour blind, If one is dominant then out of every four children one will be colour blind, If he possese two alleles that are recessive none of his offspring will be colour blind.
50%
Zero chance for any daughter (she needs an X from mom and an X from dad and if dad is normal, then the daughter will only receive the normal X from him. So even if she gets a colorblind X from mom, she will not be colorblind). 50% chance for sons. Dad only contributes an X to the son. But mom can give either a normal X or a colorblind X. So there's a 50% chance of him being colorblind.
The phenotypic ratio of the offspring when a tall man marries a short woman is 3:1 (tall/short). The phenotypic ratio is figured by using the punnet square with the dominant allele for tall and the recessive allele for the short gene.
If perfect pitch is dominant you could have this. PP X pp Then all of the children will have perfect pitch. If perfect pitch is recessive, then; pp X Pp then there is only a 50% chance of any one child having perfect pitch. In the future be more precise.
75% chance of having straight hair and 25 % chance having curly Alleles Curly (woman) Curly Straight Straight Straight (guy) Straight Straight Curly
50%
there is a 50% chance that the child will be colorblind. If it is a boy, it will be colorblind, but if it is a girl, it will only be a carrier. Mother's chromosome is XrXr and Father's Chromosome is XRY, which means the children's genotypes will be XRXr if girl and XrY if a boy.
yes the children would be cause they have purebred blood in them.....
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
50%
k so. i think you meant marries a woman? lol k so its recessive carried on the X chromosome. Her father genetic make up is X^b Y. marries a woman who has the trait is X^H X^h (since its recessive and dominant overthrows recessive and she has the trait h). so use a punnet square. you should get.. two girls. one is afflicted, the other one carries the trait. two boys: a normal son, and an afflicted son. Hope this helps!
Males are more likely than females to have sex-linked traits controlled by a recessive allele because they only need one recessive allele to have the sex-linked trait. In contrast, females need two recessive alleles to have the sex-linked trait, so they have a lower probability of having it.This is best viewed with a Punnet square. Say the recessive allele that controls the sex-linked trait is Xa. XA is the dominant allele and Y is the male chromosome.Scenario #1If the mom is XA XA and marries a man with the sex-linked trait Xa Y, then none of the sons will have the sex-linked trait. All the daughters will have the mutant allele, but they will all be carriers with normal phenotypes since they only have one mutant allele.XaYXAXA XaXa YXAXA XaXa YScenario #2If the mom is XA Xa and marries a man with the sex-linked trait Xa Y, then there is a 50% chance that each child will have the sex-linked trait, regardless of sex.XaYXAXA XaXA YXaXa XaXa YScenario #3If the mom is a carrier XA Xa and marries a normal man XA Y, then there is a 50% chance each son will have the sex-linked trait. The daughters may be carriers, but none of them will have the sex-linked trait.XAYXAXA XAXA YXaXA XaXa YScenario #4If the mom has the sex-linked trait Xa Xa and marries a normal man XA Y, then all of the sons will have the sex-linked trait. The daughters will be carriers, but none of them will have the sex-linked trait.XAYXaXA XaXa YXaXA XaXa YScenario #5If the mom has the sex-linked trait Xa Xa and marries a man who also has the sex-linked trait Xa Y, then all of their children will have the sex-linked trait.XaYXaXa XaXa YXaXa XaXa YAs you can see, there are many more strikethrough outcomes (8) where the male has the sex-linked trait controlled by a recessive allele than bold outcomes (3) where the female has the sex-linked trait. Thus, males are more likely than females to have sex-linked traits controlled by a recessive allele.
In short, hemophilia has nothing to do with colorblindness, but YES, they could have a colorblind child if she is a carrier for the colorblindness gene. Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Any of her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
All Girls will be carriers of Hemophilia. All Boys will be unaffected (they won't have Hemophilia).
Firstly, if the condition is recessive, both the man and the child with the condition must have the genotype tt. The mother must have the genotype Tt. This is because if she had TT, all of the children would be Tt and not have the condition. If she were tt, she would have the condition as well. Therefore if the father has tt and the mother has Tt, the other 3 children who do not have the condition must all have the genotype Tt. So: Mother - Tt Father - tt Affected child - tt Other children - Tt
its called disgusting who marries there children unless you are in a different country but still eww
Yes, I think so. He marries Sakura Haruno and has kids.