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## Related Questions

###### Asked in Math and Arithmetic, Algebra, Trigonometry

### What is the exact trigonometric function value of cot 15 degrees?

cot(15)=1/tan(15)
Let us find tan(15)
tan(15)=tan(45-30)
tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b))
tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30))
substitute tan(45)=1 and tan(30)=1/√3 into the equation.
tan(45-30) = (1- 1/√3) / (1+1/√3)
=(√3-1)/(√3+1)
The exact value of cot(15) is the reciprocal of the above which
is:
(√3+1) /(√3-1)

###### Asked in Math and Arithmetic, Algebra, Geometry

### How do you find the tangent of a triangle?

that queation doesnt make any sence u retard because u cant get
the tan of a triangle u can only get the tan of a number
To find the tan of an angle you want to use this ratio:
Opposite side divided by adjacent side
Once you find the answer, on a scientific calculator you enter
in your answer and hit the inv button then the tan button and it
should give you your answer.

###### Asked in Skin Care, Beauty

### What is the best fake tan?

###### Asked in Visayan History

### How do you say mactan?

"How to say Mactan?", you asked. Well, here's how:
mək TäN' You say Mactan (as in the name of the Filipino Island)
like this:
Say Mac as in McDonald's --- the fast-food restaurant
Say tän as in Täng (it sounds like TOWN). By the way, Täng
is
A Chinese dynasty (618-907) that was known for its wealth and its
encouragement of the arts and literature.
Say Mactan at least 25 times, and you will remember it for
life:
mac TAN mac TAN mac TAN mac TAN mac TAN mac TAN mac TAN mac TAN
mac TAN macTAN mac TAN mac TAN mac TAN mac TAN mac TAN mac TAN mac
TAN mac TAN
mac TAN mac TAN mac TAN mac TAN mac TAN mac TAN mac TAN mac TAN
mac TAN macTAN mac TAN mac TAN mac TAN mac TAN mac TAN mac TAN mac
TAN mac TAN

###### Asked in Trigonometry

### What is tan20tan32 plus tan32tan38 plus tan38tan20?

This may not be the most efficient method but
...
Let the three angle be A, B and C.
Then note that A + B + C = 20+32+38 = 90
so that C = 90-A+B.
Therefore,
sin(C) = sin[(90-(A+B) = cos(A+B)
and cos(C) = cos[(90-(A+B) = sin(A+B).
So that tan(C) = sin(C)/cos(C) = cos(A+B) /
sin(A+B) = cot(A+B)
Now, tan(A+B) = [tan(A)+tan(B)] / [1-
tan(A)*tan(B)]
so cot(A+B) = [1- tan(A)*tan(B)] /
[tan(A)+tan(B)]
The given expressin is
tan(A)*tan(B) + tan(B)*tan(C) +
tan(C)*tan(A)
= tan(A)*tan(B) + [tan(B) +
tan(A)]*cot(A+B)
substituting for cot(A+B) gives
= tan(A)*tan(B) + [tan(B) + tan(A)]*[1-
tan(A)*tan(B)]/[tan(A)+tan(B)]
cancelling [tan(B) + tan(A)] and [tan(A) +
tan(B)], which are equal, in the second expression.
= tan(A)*tan(B) + [1- tan(A)*tan(B)]
= 1