Freezing point depression is more significant if a molecule dissociates. It is the molality of the solution of osmotically active particles and freezing/melting point constant (k) of the solvent that determine the magnitude of freezing point depression.
In these experiments, we are usually measuring freezing point depression to determine molar mass of the unknown solute. The calculated molar mass would be would be lower than the actual mass of the intact molecule. If you have half as many intact particles, the intact molecular weight must be double to obtain the same formula ratio:
MW = g / mol ... since mol actually less of the intact particle, MW must be more
Freezing point depression. When a solution is formed the molecules of the solute prevent the solution from freezing at its normal freezing point, it must be colder.
The solution has a freezing point of 2.79 and this is the frezzing point of mercury
Ionic compounds are dissociated in water solution.
-0.37 C
look at Calculate_the_boiling_point_elevation_of_an_aqueous_solution_of_0.0500_m_CaCl2_Assume_complete_dissociationvery similar questionanswer is 1.64 lower than the originial freezing pointif the freezing point is 0 for example the freezing point depression is -1.64
f.p depression = (freezing point of pure solvent)-(freezing point of solution) -------> 178.4-166.2=12.2
Freezing point depression. When a solution is formed the molecules of the solute prevent the solution from freezing at its normal freezing point, it must be colder.
The solution has a freezing point of 2.79 and this is the frezzing point of mercury
Ionic compounds are dissociated in water solution.
-0.37 C
look at Calculate_the_boiling_point_elevation_of_an_aqueous_solution_of_0.0500_m_CaCl2_Assume_complete_dissociationvery similar questionanswer is 1.64 lower than the originial freezing pointif the freezing point is 0 for example the freezing point depression is -1.64
Increasing the concentration of a solute the freezing point depression is increased.
Salt is dissociated in ions in the solution; sugar is not dissociated.
Salt is dissociated in ions in the solution; sugar is not dissociated.
You need to know the solute and the solvent and whether the solute is molecular or ionic and how many ions it contains. The formula is the change in freezing point equals the number of ions times the freezing point depression constant times the molality of the solution.
it is increased with the increasing density
A salt, acid or base which can be dissociated in ions in an aqueous solution.