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Freezing point depression is more significant if a molecule dissociates. It is the molality of the solution of osmotically active particles and freezing/melting point constant (k) of the solvent that determine the magnitude of freezing point depression.

In these experiments, we are usually measuring freezing point depression to determine molar mass of the unknown solute. The calculated molar mass would be would be lower than the actual mass of the intact molecule. If you have half as many intact particles, the intact molecular weight must be double to obtain the same formula ratio:

MW = g / mol ... since mol actually less of the intact particle, MW must be more

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Q: If each molecule of unknown had dissociated into two ions in the lauric acid solution what effect would there have been on the freezing point depression of the solution?
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