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If in a party everyone shakes everyone else and the total handshakes are 66 How many people are in the party?
Wiki User
∙ 13y ago
Answer : 12 people.
The 1st person can't shake hands with him/herself so has 11 handshakes, the 2nd person has 10 ....and so on.
The total is 11 + 10 + ....+ 3 + 2 + 1 = 66.
Another way is to use the formula to sum a range of consecutive integers from 1 to n.
The Sum = ½n(n - 1)
In this case, we can put, ½n(n - 1) = 66 then, 132 = n2 - n : n2 - n - 132 = 0
This equation can be factored, (n + 11)(n - 12) = 0
As we only require a positive integer solution, this is when n - 12 = 0, n = 12.
Wiki User
∙ 13y ago
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If ten people met at a party and they all exchanged handshakes how many handshakes were exchanged?
107 unique handshakes will be exchanged
15 friends at a party and all kisses each other then how many kisses?
This is a variation on the handshake problem which say if there are n people at a party and every one shakes hands with every other one, how many handshakes are there? It is well know that kisses in fact are cleaner than handshakes which to tend to pass diseases. So thanks for a cleaner version of this classic math problem! n(n-1)/2 is the formula for the number of handshakes OR kisses for n people at a party. If you case, 15x14/2 which is 15x7 or 105.
How many handshakes if 8 people shook hands at a party?
Assuming that each person makes a shaking partnership just once and no one shakes there own hand,Consider the situation. The eight people are in a line. The first person goes down the line shaking hands with everyone else so he shakes hands 7 times. He then sits down. The second person shakes hands with everyone left in line, six handshakes, and sits down, He has no need to shake ands with the sitting man as they already shook. The remainder follow the same procedure, shaking hands with those standing, not shaking with those sitting. The last man standing shakes with no one as no one is standing and sitsThe sum of hand shakings initiated by each person is 7+6+5+4+3+2+1+0 = 28
How many people at a party if 28 hand shakes were done and everyone only did one handshake?
28 people each shook hands once...?
How do you find number of handshakes at a party?
try it out in real life, or draw it out. Basically if you have 5 people at the party and every one shakes hands (if this is what you mean) you could do this: draw 5 dots in a circle, and draw a line between every single dot, count the lines and voila you have your answer
How many people are at a party with 741 handshakes if everyone shakes once?
371
If at a party there are a total of 741 handshakes and each person shakes hands with everyone else at the party exactly once how many people are at the party?
38
If there are 8 people at a party and every person shakes hands with everyone else at the party how many handshakes will there be?
There will be 28 handshakes. If you ask each person how many handshakes they had they will tell you 7 making 7 x 8 = 56 handshakes in all. But every hand involves two people, so every handshake has been counted twice, thus there are 56 / 2 = 28 handshakes in all.
If ten people are at a party and they all exchange handshakes how many hand shakes were exchanged?
If that happens you have to times ninexten and the answer would be 90 handshakes
Seve girls arrive at a tea party each of them shakes hands once with each of the others how many handshakes does that make?
21 handshakes
Seven people come to a party and shakes hands with each other if each person shakes the hand of every other person how many hand shakes occur?
If there are seven people, then the number of handshakes is 7*6/2 = 21
If at a party there are twelve people present Everyone has to shake hands exactly once with every other person How many handshakes are necessary?
Sixty-six unique, distinct handshakes.
At certain party there wereb 45 handshakes Everyone shook hands with everyone else exactly once how many people attended the party?
There were ten people at the party. This is a triangular sequence starting with two people: 1, 3, 6, 10, 15, 21, 28, 36, 45, etc. There's an equation for this. With n people at the party, the number of handshakes is n(n-1)/2.
If ten people met at a party and they all exchanged handshakes how many handshakes were exchanged?
107 unique handshakes will be exchanged
In a party everyone shakes hand with each other. If total number of handshakes is 780 how many people were there?
There were 40 people at the party. Let n be the number of people at the party. Each person shakes hands with every other person, so each person shakes hands with (n - 1) people, a possible total of n(n - 1) handshakes. But when person A shakes hands with person B, B also shakes hands with A, so each handshake would be counted twice. → number_of_handshakes = n(n - 1)/2 total number of handshakes is 780 → n(n - 1)/2 = 780 → n(n - 1) = 1560 → n^2 - n - 1560 = 0 As 1560 is negative, one factor is positive and one is negative, so we need the factor pair of 1560 which has a difference of 1, namely: 39 x 40 → (n - 40)(n + 39) = 0 → n = 40 or -39 There cannot be a negative number of people → there are 40 people present.
there are 3 people at a party if each person mis shake hands with every person at the party exactly once how many handshakes will there be?
So, there will be 3 handshakes among the 3 people at the party.
If there 28 handshakes how many people are at the party?
29 People including You.
