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If current in an electric stove is doubled how will the thermal energy produced per unit time change?
Wiki User
∙ 11y ago
P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.
P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.
P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.
P = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.
Wiki User
∙ 14y ago
Wiki User
∙ 11y agoDoubling the current through any conductor causes it
to dissipate 4 times as much power.
Wiki User
∙ 14y agoP = I2R (power = current squared times resistance). Therefore, if the current doubles, the amount of dissipated electrical energy will increase by a factor of 4.
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If a current in an electric stove is doubled how will the thermal energy produced per unit time change?
sera ulo
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When is thermal produced?
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What happen to thermal conductivity of a wall if its thickness is doubled?
It becomes double as K=Q/t×L/A(T2-T1) so if the thickness (L) of an object is doubled the thermal conductivity will be doubled as thermal conductivity is directly proportional to the thickness/L of the object K=L K=2L,K=2 two times
What happens to the thermal conductivity of the wall if its thickness is doubled?
It becomes double as K=Q/t×L/A(T2-T1) so if the thickness (L) of an object is doubled the thermal conductivity will be doubled as thermal conductivity is directly proportional to the thickness/L of the object K=L K=2L,K=2 two times
