# If the distance between the parallel plate capacitor is reduced to half and a dielectric of dielectric constant k is introduced then how does electric field varies?

From the formula, E = V/d, where V is the voltage and d is the
distance, it can be seen that the electric field and the distance
are inversely related. Thus, as the distance between the parallel
plate capacitors is reduced to half, **the electric field is
increased twice.** Moreover, is a dielectric constant k is
introduced, the capacitance will increase. This direct relationship
can be seen in the formula, C = [k(Єo)A]/d, where k is the
dielectric constant. The lowest possible value of k is 1; and that
is when the dielectric is a vacuum. Other dielectric constants are
greater than 1, such as teflon which has a dielectric value of 2.1
As the capacitance increases, **the electric field also
increases**. (E = 1/2(CV^2))

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