An angle and the angle that it is supplementary to have a total measure of 180 degrees.
Let x be the supplementary angle. 4x would be the original angle.
x + 4x = 180
5x = 180
x = 36
4x = 144
So the two angles are 144 degrees and 36 degrees.
Supplementary angles are angles which add to 180o. So, one angle is nine times as large as the other, therefore letting the smaller angle be X, we have the following: 9X + X = 180 10X = 180 X=18o and the other is 9 times this amount or 162o
Two supplementary angles add up to 180 degrees. If one of the angles is x degrees, then the other angle will be 3x - 60. So we have: x + 3x - 60 = 180 4x - 60 + 60 = 180 + 60 4x = 240 4x/4 = 240/4 x = 60 3x - 60 = 3(60) - 60 = 120 Thus, the angles have measures of 60 and 120 degrees.
Let the angle be A, then the supplementary angle is (180 - A) and the complementary angle is (90 - A). But, 180 - A = 10(90 - A) = 900 - 10A 9A = 720 A = 80° The supplementary angle = 100° and the complementary angle = 10°
The angles are supplementary ===> A + B = 180 ===> A = 180 - B. Next statement: 3A = 2B - 5 (We don't know or care yet which one is larger, nor do we need to. That will come out on its own.) Substitute the first into the second: 3(180-B) = 2B-5 ===> (540-3B) = (2B-5 ) ===> 540 = 5B-5 ===> 545 = 5B109 = B ===> 71 = A
Complementary angles are angles that add up to 90 degrees. If the smaller angle is x, the larger is 5x, so 6x = 90. X equals 15, and the larger angle measures 75 degrees.
Angle 'A' is 7 more than 3 times angle 'B': A = 3B + 7 The angles are supplementary: A + B = 180 or A = (180 - B) (180 - B) = 3B + 7 180 = 4B + 7 173 = 4B B = 43.25 degrees A = 136.75 degrees Their difference is 93 degrees.
Suppose the angle is x then the second is 5x. The two angles are supplementary so x + 5x = 180 or 6x = 180 so that x = 30 degrees.
Supplementary angles add up to 180°. T - 35 = 4(180 - T) = 720 - 4T 5T = 720 + 35 = 755 T = 151° and its supplementary angle is therefore 29°.
Opposite angles of a parallelogram are equal, and adjacent angles are supplementary. Let one angle be θ, then the adjacent angle is 4θ + 50° → θ + 4θ + 50° = 180° → 5θ = 130° → θ = 26° → The two adjacent angles are 26° and 154°. → The angles of the parallelogram are 26°, 154°, 26°, 154°.
Supplementary angles are angles which add to 180o. So, one angle is nine times as large as the other, therefore letting the smaller angle be X, we have the following: 9X + X = 180 10X = 180 X=18o and the other is 9 times this amount or 162o
Two supplementary angles add up to 180 degrees. If one of the angles is x degrees, then the other angle will be 3x - 60. So we have: x + 3x - 60 = 180 4x - 60 + 60 = 180 + 60 4x = 240 4x/4 = 240/4 x = 60 3x - 60 = 3(60) - 60 = 120 Thus, the angles have measures of 60 and 120 degrees.
from the given information,we get, angle b = x angle a = 4x - 5 we know that supplementary angles have 180 degree as their sum , so, 4x - 5 + x = 180 5x - 5 = 180 5x = 185 x = 37 so,angle a = 4x - 5 = 4 *37 -5 = 143 angle b = 37 also angle a + angle b = 143 + 37 = 180
Let the angle be A, then the supplementary angle is (180 - A) and the complementary angle is (90 - A). But, 180 - A = 10(90 - A) = 900 - 10A 9A = 720 A = 80° The supplementary angle = 100° and the complementary angle = 10°
The angles are supplementary ===> A + B = 180 ===> A = 180 - B. Next statement: 3A = 2B - 5 (We don't know or care yet which one is larger, nor do we need to. That will come out on its own.) Substitute the first into the second: 3(180-B) = 2B-5 ===> (540-3B) = (2B-5 ) ===> 540 = 5B-5 ===> 545 = 5B109 = B ===> 71 = A
The angle is 160 degrees and it's supplement is 20 degrees.
Complementary angles are angles that add up to 90 degrees. If the smaller angle is x, the larger is 5x, so 6x = 90. X equals 15, and the larger angle measures 75 degrees.
The angles are 157.5 degrees and 22.5 degrees