Asked in Algebra
If the perimeter of a rectangular house is 44 yards and the length is 36 feet what is the width of house?
The house is 30 ft wide. Perimeter of a rectanglw is 2L + 2W. solved: P = 2L + 2W (convert P to ft and sub known values) 132 = (2*36) + 2W (simplify) 132 = 72 + 2W (subtract 72 from each side of the equation) 60 = 2W (divide both sides of the equation by 2 to find the width) 30 = W