Yes. Each light bulb is just another resistor in a series circuit, where you add the individual resistances to get the total resistance (unless the bulbs are set up in parallel, where adding a second identical light bulb would cut the total resistance in half).
A bulb with higher resistance will make the bulb be dimmer. The light output of a bulb is related to the power rating of that bulb. P=(I^2)xR. Power is equal to the current squares times the resistance. By increasing the resistance with a constant voltage source will reduce the current. By using that equation you can see that even though your resistance is increased your current is reduced exponentially.
R=10 ohms
Ex.
V=120v
R=10 ohm
I=V/R
120/10 = 12 amps
P=(12^2)x10
=1440 watts
R=20 ohms
I=120/20
=6 amps
P=(6^2)x20
=720 watts
You can see that increasing your resistance will reduce your power output which will reduce the brightness of you bulb.
yes
As more light bulbs are added in a series circuit, the effective resistance of the circuit increases. That causes the current leaving the source to decrease.
It will decrease the effective load resistance across the power supply terminals, increase the total current through the load, and increase the total power required to be supplied by the power supply.
As you add more bulbs to a series circuit that means that the bulbs are in series to one another, therefore the total resistance is the sum of the individual resistance of the bulbs. If you add bulbs of the same resistance,then the rate at which the resistance changes will increase in a constant manner provided the current source is not altered. For instance if the bulb you are using is rated 20v,60w, then the current passing via the bulbs in series is the square of the voltage divided by the power in this case the current is approximately 7amperes.
The brightness of an incandescent light bulb depends on the voltage applied across its terminals. Connecting one, two, or five light bulbs of the same rating to a battery in parallel will provide the same brightness from each bulb.
YESAnswerNot necessarily. The current depends on the potential difference and the load resistance. If you connect cells in parallel, you do not effect its voltage or the load, so the current is unaffected (although the battery's current 'capacity' will increase). If you connect the cells in series, then you will increase the voltage and the current will increase.
As more light bulbs are added in a series circuit, the effective resistance of the circuit increases. That causes the current leaving the source to decrease.
It will decrease the effective load resistance across the power supply terminals, increase the total current through the load, and increase the total power required to be supplied by the power supply.
Since resistance is the ratio of voltage to current, if the voltage is constant then increasing the resistance will result in a reduction in current.
"http://www.tpub.com/neets/book1/chapter3/1-26.htm" This site explains how to calculate the resistance, but it decreases the resistance when you add more.
It depends what is the outcome of burning. If that light has created open circuit, circuit will break and there will not be any current. But if there is short circuit means overall resistance is decreased. Thus current will increase. Besides overall brightness will also increase. Thus, if in a series lesser the number of bulbs more will be brightness.
yes because of bulb resistance :)
A: Adding any resistance bulbs or whatever in a series circuit will reduce current and will reduce total power. In this case the bulb will glow dimmer as any additional bulbs are placed in the series circuit. this is true if the same input source is kept constant.
Two bulbs connected in parallel are brighter than two connected in series. The resistance of the circuit is lower, electrons can flow more easily.
As you add more bulbs to a series circuit that means that the bulbs are in series to one another, therefore the total resistance is the sum of the individual resistance of the bulbs. If you add bulbs of the same resistance,then the rate at which the resistance changes will increase in a constant manner provided the current source is not altered. For instance if the bulb you are using is rated 20v,60w, then the current passing via the bulbs in series is the square of the voltage divided by the power in this case the current is approximately 7amperes.
Taking some bulbs out of the circuit!! (I think :P) Taking some bulbs out of the circuit!! (I think :P) Use Ohm's law I = E/R. Add some values and check it out. You use the formula V = IR (where V and E are the same thing, voltage. I is the current. R is the resistance). If you add more resistance then your current will be lower. I would suggest looking at parallel and series resistance so that you can understand equivalent resistance.
Current decreasesWhen voltage remains constant and resistance increases the current in the circuit will reduce.More informationV=IRwhere V is voltage,I is current andR is resistance.From the above equation,R=V/I, and hence resistance is indirectly proportional to current.Therefore, an increase in resistance would have the effect of decreased current.NB: this holds true only as long as the voltage remains constant.Another opinionHowever, this is only true in the case of a circuit connected in series.When circuits are connected in parallel, the opposite happens. If there is an increase in the amount of resistors in parallel, the total resistance of the circuit then decreases and the current increases subsequently.Yet another viewNo, that's not stated right.If more resistors are added in parallel - so that the circuit's overall total resistance decreases and its total current increases - that is NOT in any way the opposite of what this question is asking about...Let's make this crystal clear, so that there is no confusion: "an increase in the amount of resistors" is NOT the same as "an increase in resistance".So a parallel circuit behaves EXACTLY the same as a series circuit: if its overall resistance increases, the overall current going through the parallel circuit decreases AND if its overall resistance decreases, the overall current going through the parallel circuit increases.Actually, the second opinion is correctIn a parallel circuit, there are more branches to allow electrons back to the power supply, so current increases. With more resistors in a circuit, the overall resistance in a parallel circuit DECREASES.In a series circuit, current is the same throughout. So if more resistors are added, resistance INCREASES and so current DECREASES.
Assuming you add more cells in series, the voltage will increase. If you don't change the resistance of the circuit, this in turn will also increase the current.